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kvasek [131]
3 years ago
8

Which process releases the energy that eventually produces lighting in a thunderstorm

Chemistry
1 answer:
Elena L [17]3 years ago
5 0
The process that releases energy which causes lightning is known as Glaciation
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Calculate the molality of a 5.51 M ethanol (C2H5OH) solution whose density is 0.9349 g/mL
bearhunter [10]

Molality of C2H5OH is 1.1.27m.



What is Molality?

Molality is no.of moles present in One Kg solution .

Molality is represented by m

m= no.of moles/ weigt of solution in kg

Given is Molarity= 51.30M

molar mass of C2H5OH is 46g / mol , Density =0.9349g/ ml

Density=m/V

V = 107 ml

Molarity= no of moles/ Volume

51.5×46×107= x × 1000

weight of C2H5OH = 27.7g

molality = 27.7/1000××46

m= 1.27m

to learn more about Molality click brainly.com/question/20380670

#SPJ9

5 0
1 year ago
What is the mole fraction of water in 200g of 95 ethanol?
deff fn [24]
             <span> If the solution is 95% by weight, that means that in 100 grams of solution you have 5 grams of water and 95 grams of ethanol.

Convert each of these masses to moles by dividing each mass by the molar mass of the compound.

5 g/18 g/mol = 0.278 mol water
95 g / 46g/mol = 2.065 mol ethanol

Mole fraction water:
= mol water / total moles
= 0.278/ (0.278 + 2.065)
= 0.119 </span>
7 0
3 years ago
Which trait will an organism that receives one dominant gene and one recessive gene most
serious [3.7K]

Answer: dominant

explanation: The dominant Gene wins because it overpowers the recessive gene.

4 0
3 years ago
Read 2 more answers
For a neutral Nitrogen, how many electrons are in the 2p electron orbitals?
Marta_Voda [28]
3 electrons would be in the 2p orbital
3 0
2 years ago
The radius of a helium atom is a 31 PM. What is the radius in nanometers?
Paladinen [302]

Answer:

Thus, the radius of the helium atom in nanometers is - 0.031 nm

Explanation:

Given that:-

The radius of the helium atom = 31 pm

Considering the conversion of length in pm to the length in nm as:-

1 pm = 0.001 nm

So,

Applying the above conversion factor in the radius of helium atom as:-

Radius = 31\times 0.001 nm = 0.031 nm

<u>Thus, the radius of the helium atom in nanometers is - 0.031 nm</u>

7 0
2 years ago
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