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ss7ja [257]
4 years ago
8

Which boiling point is lower an why?

Chemistry
2 answers:
siniylev [52]4 years ago
8 0

Answer:

4.

Explanation:

Is expected because of the stronger dipole forces in SiH4.

DiKsa [7]4 years ago
3 0

Answer:4

Explanation:

If we carefully observe the electronegativity of the elements in question

P-2.19

N-3.04

C-2.55

Si-1.9

H-2.2

SiH4 is definitely more polar than CH4 hence greater dipole forces of a higher boiling point. NH3 is more polar than PH3 hence NH3 has greater dipole forces and a higher boiling point. Electronegative differences influences the polarity of a bond. The greater the electro negativity difference between bonding atoms, the greater the dipole forces and the greater the boiling point.

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4. A galvanic cell is formed when two metals are immersed in solu- tions differing in concentration 1 when two different metals
Vanyuwa [196]

A galvanic cell is formed when two metals are immersed in solutions differing in concentration, when two different metals are immersed.

<h3><u>What is a </u><u>Galvanic</u><u> </u><u>cell</u><u> ?</u></h3>
  • In order to provide a pathway for the flow of electrons along that wire, the galvanic cell makes use of the ability to split the flow of electrons during the oxidation and reduction processes.
  • It forces a half-reaction and connects each to the other with a wire.
  • A galvanic cell is an electrochemical device that converts chemical redox reaction energy into electrical energy.
  • Electrically, it has a potential of 1.1 V. Oxidation takes place at the anode, which is a negative plate in galvanic cells. It is a positive plate where the reduction happens.
  • An electrochemical device called a galvanic cell transforms chemical energy's free energy into electrical energy. A photogalvanic cell produces species that are photochemically reactive.

To view more questions about galvanic cell, refer to:

brainly.com/question/13031093

#SPJ4

5 0
2 years ago
What is the rate law for the reaction 2A + 2B + 2C --&gt; products
-Dominant- [34]

Answer:

R = 47.19 [A]*([B]^2)*[C]

Explanation:

The rate law for the reaction 2A + 2B + 2C --> products

Is being sought.

The reaction rate R could be expressed as  

R = k ([A]^m)*([B]^n)*([C]^p)                      (1)

where m, n, and p are the reaction orders with respect to (w.r.t.) components A, B and C respectively. This could be reduced to

R = ka ([A]^m)                   (2)

Where ka=(k[B]^n)*([C]^p);    

R = kb ([B]^n)                    (3)

Where kb=(k[A]^m)*([C]^p); and  

R = kc ([C]^p)                     (4)

Where kc=(k[A]^m)*([B]^n).

Equations (2), (3) and (4) are obtained for cases when the concentrations of two components are kept constant, while only one component’s concentration is varied. We can determine the reaction wrt each component by employing these equations.  

The readability is very much enhanced when the given data is presented in the following manner:

Initial [A]  0.273   0.819   0.273   0.273

Initial [B]  0.763   0.763   1.526   0.763

Initial [C]  0.400   0.400    0.400   0.800

Rate           3.0       9.0       12.0       6.0

Run#  1  2 3  4

Additional row is added to indicate the run # for each experiment for easy reference.

First, we use the initial rate method to evaluate the reaction order w.r.t. each component [A], [B] and [C] based on the equations (2), (3) and (4) above.

Let us start with the order wrt [A]. From the given data, for experimental runs 1 and 2, the concentrations of reactants B and C were kept constant.

Increasing [A] from 0.273 to 0.819 lead to the change of R from 3.0 to 9.0, hence we can apply the relation based on equation (2) between the final rate R2, the initial rate R1 and the final concentration [A2] and the initial concentration [A1] as follows:

R2/R1=ka[A2]^m/ka[A1]^m=([A2]/[A1])^m

9.0/3.0 = (0.819/0.273)^m

3 = (3)^m = 3^1  -> m = 1

Similarly, applying experimental runs 1 and 3 could be applied for the determination of n, by employing equation (3):  

R3/R1=kb[B3]^n/kb[B1]^n=([B3]/[B1])^n

12/3= (1.526/0.763)^n

4= 2^n, -> n = 2

And finally for the determination of p we have using runs 4 and 1:

R4/R1=kc[C4]^p/kc[C1]^p=([C4]/[C1])^p

6/3= (0.8/0.4)^p

2= 2^p , -> p = 1

Therefore, plugging in the values of m, n and p into equation (1), the rate law for the reaction will be:

R = k [A]*([B]^2)*[C]

The value of the rate constant k could be estimated by making it the subject of the formula, and inserting the given values, say in run 1:

k = R /( [A]*([B]^2)*[C]) = 3/0.273*(0.763^2)*0.4 =

47.19

Finally, the rate law is

R = 47.19 [A]*([B]^2)*[C]

7 0
4 years ago
A sunscreen preparation contains 2.50% benzyl salicylate by mass. If a tube contains 4.0 oz
antoniya [11.8K]

About 0.92 kg of benzyl salicylate would be needed in order to manufacture 325 tubes of sunscreen.

A tube contains 4.0 oz of the sunscreen and each one 2.5% benzyl salicylate.

         2.5% of 4.0 oz = 0.1 oz

Thus, each tube would need 0.1 oz of benzyl salicylate.

325 tubes of the sunscreen is needed and each one requires 0.1 oz of benzyl salicylate. Hence, total amount of benzyl salicylate needed would be:

    325 x 0.1 oz = 32.5 oz

From conversion:

16 oz = 1 lb

Hence,

32.5 oz = 32.5/16

                        = 2.03 lb

Also:

2.205 lb = 1 kg

2.03 lb = 2.03/2.205

             = 0.92 kg

More on dimensional analysis can be found here: brainly.com/question/22015862

6 0
3 years ago
Calculate the value of q (kj) in this exothermic reaction when 5.40 g of hydrogen peroxide decomposes at constant pressure?
Gelneren [198K]
Hydrogen peroxide decomposes to yield water and oxygen gas 
That is; H2O2 (l) = H2O (l) + O2(g)
The standard heat of formation; H2O2 (l) = -187.6 kJ/mol; H2O(l) = -285.8 kJ/mol
1 mole of hydrogen peroxide contains 34 g
Thus, 5.4 g contains 5.4/34 = 0.1588 moles 
The moles of water produced will also be equivalent to 0.1588 moles 
Heat = heat of formation of product - reactant
Therefore; Heat = (0.1588 moles × -285,8 )- (0.1588× -187.6)
                           =  -15.594 kJ
6 0
3 years ago
Name the following base: NaOH
soldier1979 [14.2K]

Answer:

Arrhenius Base

Explanation:

"NaOH is an Arrhenius base because it dissociates in water to give the hydroxide (OH-) and sodium (Na+) ions. An Arrhenius acid is therefore any substance that ionizes when it dissolves in water to give the H+, or hydrogen, ion. ... Acids provide the H+ ion; bases provide the OH- ion; and these ions combine to form water."

==================================================================

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8 0
3 years ago
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