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Vesnalui [34]
3 years ago
9

The final stages of a star's life depend on its mas. true or false?​

Physics
1 answer:
Diano4ka-milaya [45]3 years ago
5 0

Answer:

TRUE

Explanation:

Low mass stars last lots longer.

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D. the motion of the source or observer
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Which pair of triangles can be proven congruent by the hl theorem?
hoa [83]

The pairs of triangles that can be proven congruent by the hl theorem is the right angled triangle.

<h3>What is mearnt be the HL theorm?</h3>

The HL theorem is also known as the Hypothenus Leg theorem, it states that "the hypotenuse and leg of one right triangle are congruent to the hypotenuse and leg of another right triangle, then the two triangles are congruent."

Learn more about the postulates of the HL theorem here:

brainly.com/question/25922842

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Prove that..<br>please help<br>​
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\large{ \boxed{ \bf{ \color{red}{Universal \: law \: of \: gravitation}}}}

Every object in the universe attracts every other object with a force which is proportional to the product of their masses and inversely proportional to the square of the distance between them. The forces along the line joining the centre of the two objects.

❍ Let us consider two masses m1 and m2 line at a separation distance d. Let the force of attraction between the two objects be F.

According to universal law of gravitation,

\large{ \longrightarrow{ \rm{F \propto m_1 m_2}}}

Also,

\large{ \longrightarrow{ \rm{ F \propto  \dfrac{1}{ {d}^{2} } }}}

Combining both, We will get

\large{ \longrightarrow{ \rm{F  \propto  \dfrac{ m_1 m_2}{ {d}^{2}}}}}

Or, We can write it as,

\large{ \longrightarrow{ \rm{F  \propto  \:  G \dfrac{ m_1 m_2}{ {d}^{2} }}}}

Where, G is the constant of proportionality and it is called 'Universal Gravitational constant'.

☯️ Hence, derived !!

<u>━━━━━━━━━━━━━━━━━━━━</u>

8 0
3 years ago
Alexandra drops an egg from 30 m above the ground to hit Vanessa on the head. If Vanessa stands 3.5 meters tall. How fast is the
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This is problem of free falling objects, which can be solved using the formula:

V = sqrt(2gy)

Where v is the velocity upon impact

G is the acceleration due to gravity ( 9.81 m/s2)

Y is the height

Since Venessa is 3.5 m

Y = 30 -3.5 = 26.5 m

V = sqrt(2 (9.81 m/s2) ( 26.5 m))

<span>V = 22.8 m/s</span>

7 0
3 years ago
Carlos pushes a 3 kg box with a force of 9 newtons. The force of friction on the box is 3 newtons in the opposite direction. Wha
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The 'net' force acting on the box is (9 - 3) = 6 newtons
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Force = (mass) x (acceleration)

6 = (3) x (acceleration)

Divide each side by 3 :

<em>2 m/s² = acceleration</em>
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