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3 years ago

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A school bus takes 0.53 hours to reach the school from your house. If the average speed of the bus is 19km/h, what is the displa

cement of the bus during the trip?

2 answers:

Artist 52 [7]3 years ago

5 0

D = v*t= 19*0,53 = 10.07 km

Harlamova29_29 [7]3 years ago

4 0

Answer:

The displacement of the bus during the trip is 10.07 km.

Explanation:

Given that,

Time = 0.53 h

Average speed of bus = 19 km/h

We need to calculate the displacement of the bus

Using formula of average velocity

$v_{av}=\dfrac{D}{t}$

$D = v_{avg}\times t$

Where, D = displacement

t = time

Put the value into the formula

$D=19\times0.53$

$D=10.07\ km$

Hence, The displacement of the bus during the trip is 10.07 km.

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A train at a constant 79.0 km/h moves east for 27.0 min, then in a direction 50.0° east of due north for 29.0 min, and then west

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Answer:

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$\vec{s_{net}} = 16.03\hat{i} + 24.54\hat{j} km$

(a) Now, average velocity, $v_{avg}$ is given:

$v_{avg} = \frac{total displacement, \vec{s_{net}}}{total time, t}$

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(b) angle can be calculated as:

$tan\theta' = \frac{15.83}{10.34}$

$\theta' = tan^{- 1}\frac{15.83}{10.34} = 56.85^{\circ}$

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