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Usimov [2.4K]
3 years ago
9

A school bus takes 0.53 hours to reach the school from your house. If the average speed of the bus is 19km/h, what is the displa

cement of the bus during the trip?
Physics
2 answers:
Artist 52 [7]3 years ago
5 0
D = v*t= 19*0,53 = 10.07 km
Harlamova29_29 [7]3 years ago
4 0

Answer:

The displacement of the bus during the trip is 10.07 km.

Explanation:

Given that,

Time = 0.53 h

Average speed of bus = 19 km/h

We need to calculate the displacement of the bus

Using formula of average velocity

v_{av}=\dfrac{D}{t}

D = v_{avg}\times t

Where, D = displacement

t = time

Put the value into the formula

D=19\times0.53

D=10.07\ km

Hence, The displacement of the bus during the trip is 10.07 km.

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Answer:

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f(t) = f₁₂ + f₃₂

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q₁  = + 8 μC     then   q₁ = 8*10⁻⁶ C

q₂ =  + 3,5 μC  then  q₂ = 3,5 *10⁻⁶ C

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f₁₂ = 9*10⁹ * 8*3,5*10⁻¹²/ 1*10⁻²   [ N*m² /C²]* C*C/m²

f₁₂ = 252*10⁻¹ [N]

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f₃₂ =  9*10⁹*3,5*10⁻⁶*2,5*10⁻⁶ /(0,15)²

f₃₂ =  78,75*10⁻³/ 2,25*10⁻²

f₃₂ =  35 *10⁻¹

f₃₂ =  3,5 [N]

f(t) =  28,7 [N]

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2 years ago
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