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Usimov [2.4K]
3 years ago
9

A school bus takes 0.53 hours to reach the school from your house. If the average speed of the bus is 19km/h, what is the displa

cement of the bus during the trip?
Physics
2 answers:
Artist 52 [7]3 years ago
5 0
D = v*t= 19*0,53 = 10.07 km
Harlamova29_29 [7]3 years ago
4 0

Answer:

The displacement of the bus during the trip is 10.07 km.

Explanation:

Given that,

Time = 0.53 h

Average speed of bus = 19 km/h

We need to calculate the displacement of the bus

Using formula of average velocity

v_{av}=\dfrac{D}{t}

D = v_{avg}\times t

Where, D = displacement

t = time

Put the value into the formula

D=19\times0.53

D=10.07\ km

Hence, The displacement of the bus during the trip is 10.07 km.

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A piano wire with mass 2.95 g and length 79.0 cm is stretched with a tension of 29.0 N . A wave with frequency 105 Hz and amplit
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The concept needed to solve this problem is average power dissipated by a wave on a string. This expression ca be defined as

P = \frac{1}{2} \mu \omega^2 A^2 v

Here,

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\omega =  Angular frequency of the wave on the string

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At the same time each of this terms have its own definition, i.e,

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Replacing this terms and the first equation we have that

P = \frac{1}{2} (\frac{m}{l})(2\pi f)^2 A^2(\sqrt{\frac{T}{\mu}})

P = \frac{1}{2} (\frac{m}{l})(2\pi f)^2 A^2 (\sqrt{\frac{T}{m/l}})

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PART A ) Replacing our values here we have that

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What is the acceleration of an object with a mass of 15 kg and a coefficient of friction of 0.18
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Answer:

a = 1.764m/s^2

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