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Gala2k [10]
3 years ago
14

Which statement best explains the relationship between the electric force between two charged objects and the distance between t

hem?
Physics
1 answer:
spin [16.1K]3 years ago
3 0
Unfortunately, the given statements are missing from the problem. However, we can still determine the relationship between the electric force between two objects and the distance between them. The formula for the electric force is given below:

F = (k*Q1*Q2)/d^2

k is a constant, while Q1 and Q2 are the respective charges of the objects. F is force, while d is distance.

As seen in the formula, we can see that the electric force F is inversely proportional to the square of the distance between the two objects.
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What distance will a vehicle travel before coming to a complete stop from a speed of 70 mph, (a) When the vehicle is traveling o
OLga [1]

Answer:

(a), The SSD will be 723.9 ft.

(b-1), The SSD will be 620.2 ft.

(b-2), The SSD will be 723.91>SSD>620.2

(c), The SSD will be 910.5 ft.

Explanation:

Given that,

Speed = 70 mph

Suppose, a perception reaction time of 2.5 sec and the coefficient of friction is 0.35

We need to calculate the stopping sight distance

Using formula of SSD

SSD=1.47\times v\times t+\dfrac{v^2}{30\times(f\pm g)}

Where, v = speed of vehicle

t = perception reaction time

f = coefficient of friction

g = gradient of road

(a). If the gradient of road is zero.

Then, the stopping sight distance will be

SSD=1.47\times 70\times 2.5+\dfrac{70^2}{30\times(0.35)}

SSD=723.9\ ft

(b-1). If the gradient of road is 0.1

Then, the stopping sight distance will be

SSD=1.47\times 70\times 2.5+\dfrac{70^2}{30\times(0.35+0.1)}

SSD=620.2\ ft

(b-2). If the grade continuously decrease then the SSD will be increase.

But if the grade is increase then the SSD will be decrease and for flat grade the SSD will be more.

So, The SSD will be 723.91>SSD>620.2

(c). When the vehicle is traveling downhill on a roadway of constant grade then the vehicle take will be more SSD

So, The SSD will be

SSD=1.47\times 70\times 2.5+\dfrac{70^2}{30\times(0.35-0.1)}

SSD=910.5\ ft

Hence, (a), The SSD will be 723.9 ft.

(b-1), The SSD will be 620.2 ft.

(b-2), The SSD will be 723.91>SSD>620.2

(c), The SSD will be 910.5 ft.

7 0
3 years ago
An electron with a charge of -1.6 × 10-19 coulombs experiences a field of 1.4 × 105 newtons/coulomb. What is the magnitude of th
kipiarov [429]

Answer:

2.24 \times 10^{-14} Newtons

Explanation:

Magnitude of charge on the electron = q = 1.6 \times 10^{-19} Coulombs

The negative sign in the question statement indicates that the charge is negative.

Magnitude of Electric Field experienced by the electron = E = 1.4 \times 10^{5} Newtons/Coulomb

Magnitude of Force on the electron = F = ?

The relation between the charge, electric field and the force on the charge because of electric field is given by:

E=\frac{F}{q}

From here we can write:

F = qE

Using the values, we get:

F = 1.6 \times 10^{-19} \times 1.4 \times 10^{5}\\\\ F = 2.24 \times 10^{-14}

Thus, the magnitude of the electric force experience by the electron would be 2.24 \times 10^{-14} Newtons

8 0
3 years ago
Based on the TIA/EIA 568-B structured cabling standard, the cabling that runs from the telecommunications closet to each work ar
lana [24]

Answer:

False.

Explanation:

Backbone Cabling: A system of cabling that connects the equipment rooms and telecommunications rooms.

Horizontal Cabling: The system of cabling that connects telecommunications rooms to individual outlets or work areas on the floor.

4 0
4 years ago
an object is moving with initial velocity of 5 m/s. After 10 seconds final velocity is 10 m/s. Calculate its acceleration.​
Brut [27]

Answer:

0.5m/s2

Explanation:

acceleration= change in velocity/time taken

= v - u/ t

= 10-5/10

=5/10

= 0.5m/s2

6 0
3 years ago
A small electric motor produces a force of 5 N that moves a remote-control car 5 m every second. How much power does the motor p
kati45 [8]

Answer:

Explanation:

Given:

Force, f = 5 N

Velocity, v = 5 m/s

Power, p = energy/time

Energy = mass × acceleration × distance

Poer, p = force × velocity

= 5 × 5

= 25 W.

Note 1 watt = 0.00134 horsepower

But 25 watt,

0.00134 hp/1 watt × 25 watt

= 0.0335 hp.

4 0
3 years ago
Read 2 more answers
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