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lisabon 2012 [21]
4 years ago
12

How can you which molecule is positive and negative in a dipole-dipole relationship?

Chemistry
1 answer:
marysya [2.9K]4 years ago
5 0
Dipole interactions are observed in covalent bonds. In ionic bonding, permanent transfer of electrons occurs and due to this dipole-dipole interactions are not observed. In covalent bonding, electron cloud is shared between 2 atoms. If this electron cloud is not shared equally between them, polarities are formed in a molecule. And hence we say that the molecule is polar. For a molecule to be polar, there should be electronegativity difference between them. Atom with greater electronegative attracts electron cloud more towards itself whereas atom with lesser electronegative attracts electron cloud less. But there is no permanent transfer of electrons. Due to this electronegativity differences, atom with more electronegative gains partial negative charge and atom with lesser electronegative value gains partial positive charge. The charge is partial because there is no complete transfer of electrons.
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Fuel
VikaD [51]

Answer:

Part 1

Where we have that the phase temperature at which fuel 1 changes to liquid due to its low temperature after the energy transfer is reached, fuel 1 changes to liquid

Where we have that the temperature of fuel 2 is still above its gas to liquid phase transition temperature, the fuel in fuel 2 will remain gaseous

Part 2

The kinetic energy of the individual molecules in fuel 1 is less than the intermolecular forces holding the molecules of fuel 1 in the liquid state such that fuel 1 molecules undergoes phase transformation from gas to liquid

The kinetic energy of the molecules in fuel 2 is higher than the fuel 2 liquid state intermolecular forces fuel 2 does not undergo phase transformation and remain a gas

Explanation:

Part 1

Why fuel 1 change phase but fuel 2 stayed the same can be explained by the combination of the following physical phenomena

1) Specific heat capacity of the fuels

2) Phase transition temperature of the fuels

The energy transferred out, ΔQ, can be expressed as follows;

ΔQ = m·c·ΔT

Where;

m = The mass of the fuel

c = The specific heat capacity of the fuel

ΔT = The temperature change of the fuel

Therefore, the energy transferred out, for a given mass of fuel, is directly proportional to the specific heat capacity, and the temperature change

For a given amount of transferred energy, when the specific heat capacity is high, the temperature change will be low and vice versa

Taking the specific heat capacity of fuel 1, c₁ as lower than the specific heat capacity of fuel 2, c₂₂, we have;

For a given energy transferred out, when c₁ < c₂ then we have, ΔT₁ > ΔT₂

The temperature change of fuel 1 is more than the temperature change of fuel 2 and if both fuels where initially at the same temperature and have the same mass, the final temperature of fuel T_{1f} will be lower than the final temperature of fuel 2, T_{2f}

2) The phase transition temperature is the temperature at which a material changes phase from solid to liquid, or liquid to gas and vice versa, and it is dependent on the intermolecular holding the molecules of the substances together

Whereby the phase temperature at which fuel 1 changes to liquid due to its low temperature after the energy transfer is reached, while the temperature in fuel 2 is still above its gas to liquid phase transition temperature, the gaseous fuel in fuel 1 will be changed to liquid, while the fuel in fuel 2 will remain gaseous

Part 2

After the energy is transferred out, the kinetic energy of the individual molecules in fuel 1 becomes lower than the intermolecular forces holding the molecules of fuel 1 in the liquid state and the fuel 1 molecules transforms from gas to liquid

However, after the given amount of energy is transferred out, the kinetic energy of the molecules in fuel 2 are still higher than the intermolecular forces that exists between the molecules of fuel 2 when in the liquid state, and therefore, fuel 2 remains gaseous

3 0
3 years ago
What is the parent isotope when Cl-33 is formed during a beta decay?
zzz [600]

Answer:

33/16 S

Explanation:

In beta decay, the atomic number of the daughter nucleus increases by one unit while the mass of the daughter nucleus remains the same as that of the parent nucleus.

Hence, if we know that a beta decay has occurred, then the parent nucleus must have the same mass as its daughter nucleus but have an atomic number that is less than that of the daughter nucleus by only one unit, hence the answer above.

7 0
4 years ago
Na2SiO3 (s) + 8HF(aq) → H2SiF6 (aq) +2 NaF(aq) + 3H2O (l)
jek_recluse [69]

Answer:

honestly

idek what all that is

if your this far into what ever this is

id quit and just live life

Explanation:

7 0
4 years ago
1.If 6 moles of KNO3 should be produced in a reaction, but only 4.78 mol KNO3 are produced, what is the % yield?
irakobra [83]

Answer:

79.7%

Explanation:

Percent yield of reaction is defined as the ratio between theoretical yield of a reaction and actual yield obtained.

In the problem, theoretical yield are 6 moles of KNO₃ and actual yield are 4.78 moles. Thus, percent yield is:

4.78 mol / 6 mol × 100 =<em> 79.7%</em>

3 0
3 years ago
What is the windward side of the sand dune
earnstyle [38]

Answer:

A dunes windward side is the side where the wind is blowing and pushing material up. A dunes slip face is simply the side without wind. A slipface is usually smoother than a dunes windward side. A collection of dunes is called a dune belt or dune field.

Explanation:

Hope this helps...

7 0
3 years ago
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