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lisabon 2012 [21]
3 years ago
12

How can you which molecule is positive and negative in a dipole-dipole relationship?

Chemistry
1 answer:
marysya [2.9K]3 years ago
5 0
Dipole interactions are observed in covalent bonds. In ionic bonding, permanent transfer of electrons occurs and due to this dipole-dipole interactions are not observed. In covalent bonding, electron cloud is shared between 2 atoms. If this electron cloud is not shared equally between them, polarities are formed in a molecule. And hence we say that the molecule is polar. For a molecule to be polar, there should be electronegativity difference between them. Atom with greater electronegative attracts electron cloud more towards itself whereas atom with lesser electronegative attracts electron cloud less. But there is no permanent transfer of electrons. Due to this electronegativity differences, atom with more electronegative gains partial negative charge and atom with lesser electronegative value gains partial positive charge. The charge is partial because there is no complete transfer of electrons.
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Answer:

1 is true 2 is flase and 3 is true

Explanation:

7 0
2 years ago
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How are the excited electrons from stage 1 used in stage 2 of photosynthesis? A. Splitting of water b. Carbon fixation c. Format
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Answer;

D. Formation of NADPH

Explanation;

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3 years ago
The name of the compound with the formula ZnBr2 is
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A 1.00 liter solution contains 0.49 moles hydrocyanic acid and 0.38 moles sodium cyanide . If 0.19 moles of hydrochloric acid ar
kompoz [17]

Answer:

A)true

B)false

C)true

D)false

E)false

Explanation:

Step 1: Data given

Volume = 1.00 L

Number of moles HCN = 0.49 moles

Number of moles NaCN = 0.38 moles

Number of moles HCl added = 0.19 moles

Step 2:

This is a buffer system consisting of a weak acid, HCN and the salt of that acid, NaCN.

Upon addition of hydrochloric acid (HCl), HCN is formed and NaCl is used up.

HCl + NaCN ⇔ NaCl + HCN

A. The number of moles of HCN will increase. This is true.

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C. The equilibrium concentration of H3O will increase.  

 ⇒ True, The [H3O+] will increase slightly.

D. The pH will increase.

⇒ False, The pH will decrease slightly because acid is being added and being converted to HCN

E. The ratio of [HCN] / [CN-] will remain the same.

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3 years ago
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Answer:

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