Ask question

Ask question

All categories

lisabon 2012 [21]

3 years ago

12

How can you which molecule is positive and negative in a dipole-dipole relationship?

1 answer:

marysya [2.9K]3 years ago

5 0

Dipole interactions are observed in covalent bonds. In ionic bonding, permanent transfer of electrons occurs and due to this dipole-dipole interactions are not observed. In covalent bonding, electron cloud is shared between 2 atoms. If this electron cloud is not shared equally between them, polarities are formed in a molecule. And hence we say that the molecule is polar. For a molecule to be polar, there should be electronegativity difference between them. Atom with greater electronegative attracts electron cloud more towards itself whereas atom with lesser electronegative attracts electron cloud less. But there is no permanent transfer of electrons. Due to this electronegativity differences, atom with more electronegative gains partial negative charge and atom with lesser electronegative value gains partial positive charge. The charge is partial because there is no complete transfer of electrons.

You might be interested in

Calculate the mass of CaCl2 ( formula wt. = 110.99) thatshould

NNADVOKAT [17]

Answer: 5622.6g

Explanation:

Note: Kf for water is 1.86°C/m.

The simple calculation is in the attachment below.

7 0

2 years ago

How many electrons are in the highest energy orbital of the element copper?

iris [78.8K]

<span>the answer is 1 the 4s1 electron........................

</span><span>
</span>

5 0

2 years ago

What is needed to release the energy in a bond?

IRISSAK [1]

Answer:

More Energy

Explanation:

Energy is required to break bonds

3 0

2 years ago

Read 2 more answers

A method used by the U.S. Environmental Protection Agency (EPA) for determining the concentration of ozone in air is to pass the

baherus [9]

Answer: 1. $9.08\times 10^{-6}$ moles

2. 90 mg

Explanation:

$O_3(g)+2NaI(aq)+H_2O(l) \rightarrow O_2(g)+I_2(s)+2NaOH(aq)$

According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

Thus $4.54 \times 10^{-6}$ moles of ozone is removed by = $\frac{2}{1}\times 4.54 \times 10^{-6}=9.08\times 10^{-6}$ moles of sodium iodide.

Thus $9.08\times 10^{-6}$ moles of sodium iodide are needed to remove $4.54\times 10^{-6}$ moles of $O_3$

2. $\text{Number of moles of ozone}=\frac{0.01331g}{48g/mol}=0.0003moles$

According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

Thus 0.0003 moles of ozone is removed by = $\frac{2}{1}\times 0.0003=0.0006$ moles of sodium iodide.

Mass of sodium iodide= $moles\times {\text {molar mass}}=0.0006\times 150g/mol=0.09g=90mg$ (1g=1000mg)

Thus 90 mg of sodium iodide are needed to remove 13.31 mg of $O_3$ .

3 0

2 years ago

Calculate the percent errorin a length measurementof 4.45cm if the correct value is 4.06

FinnZ [79.3K]

Answer:

9.6 %

Explanation:

<u>Step 1: How to define percent error ? </u>

⇒ % error is the difference between a measured value and the known or accepted value

⇒Percent error is calculated using the following formula:

⇒%error = | Experimental value-theoretical value/theoretical value | x100%

⇔ this can be written as well as : error = (| Experimental value/ theoretical value | - | Theoretical value / Theoretical value | ) x100%

<u>Step 2: Calculate % error</u>

In this case, this means :

%error = ( |(4.45 cm - 4.06cm ) / 4.06cm | ) x100%

%error = 0.096 x100%

%error =9.6 %

3 0

2 years ago