A robot standing on a cliff shoots a ball upwards with an initial speed of 30 m/s. What is the height of the cliff given that th
e ball reaches the bottom of the cliff 8 s after the shoot? (Take g = 10 m/s^2 and the height of the robot is negligible.)
A 25 m
B 45 m
C 80 m
D 145 m
A 25 m
B 45 m
C 80 m
D 145 m
1 answer:
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Answer:
(a)
(b) It won't hit
(c) 110 m
Explanation:
(a) the car velocity is the initial velocity (at rest so 0) plus product of acceleration and time t1
(b) The velocity of the car before the driver begins braking is
The driver brakes hard and come to rest for t2 = 5s. This means the deceleration of the driver during braking process is
We can use the following equation of motion to calculate how far the car has travel since braking to stop
Also the distance from start to where the driver starts braking is
So the total distance from rest to stop is 352 + 88 = 440 m < 550 m so the car won't hit the limb
(c) The distance from the limb to where the car stops is 550 - 440 = 110 m
Explanation:
- Speed is the rate of change of distance with time.
Speed =
- Velocity is given as the displacement per unit of time:
Velocity =
Speed and velocity are similar but speed is a scalar quantity while velocity is a vector quantity. Speed has magnitude but does not point towards a specific direction. Velocity shows both magnitude and direction and it is a vector quantity.
- Acceleration is given as the change in velocity with time. It is a vector quantity:
Acceleration =
- Distance is how far a body moves. It is scalar quantity.
- Time is the duration of an event. It is a scalar quantity.
Learn more:
Vector calculation brainly.com/question/2678571
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