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alexandr1967 [171]
4 years ago
13

Which describes the properties reflection, absorption, and transmission when the light is shining on the oval end of a silver sp

oon?
A. It reflects all lights, transmits all light, and absorbs some lights
B. It reflects a lot of light, transmits almost no light, and absorbs some light.
C. It reflects some light, transmits some light, and absorbs almost no light.
D. It reflects almost no light, transmits almost no light, and absorbs almost no light.
Physics
1 answer:
I am Lyosha [343]4 years ago
5 0

B. It reflects a lot of light, transmits almost no light, and absorbs some light.


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A sphere of radius 5.15 cm and uniform surface charge density +12.1 µC/m2 exerts an electrostatic force of magnitude 35.9 ✕ 10-3
rosijanka [135]
The radius of the sphere is r=5.15 cm=0.0515 m, and its surface is given by
A=4 \pi r^2 = 4 \pi (0.0515 m)^2 = 0.033 m^2

So the total charge on the surface of the sphere is, using the charge density 
\rho=+1.21  \mu C/m^2 = +1.21 \cdot 10^{-6} C/m^2:
Q= \rho A = (+1.21 \cdot 10^{-6} C/m^2)(0.033 m^2)=4.03 \cdot 10^{-8}C

The electrostatic force between the sphere and the point charge is:
F=k_e  \frac{Qq}{r^2}
where
ke is the Coulomb's constant
Q is the charge on the sphere
q=+1.75 \muC = +1.75 \cdot 10^{-6}C is the point charge
r is their separation

Re-arranging the equation, we can find the separation between the sphere and the point charge:
r=\sqrt{ \frac{k_e Q q}{F} }= \sqrt{ \frac{(8.99 \cdot 10^9 Nm^2 C^{-2})(4.03 \cdot 10^{-8} C)(1.75 \cdot 10^{-6}C)}{35.9 \cdot 10^{-3}N} }=0.133 m=13.3 cm
8 0
3 years ago
What makes a planet different from other celestial bodies?.
Serggg [28]

Answer:

It's more habitable.

Explanation:

The atmosphere, calculated to equations, are a lot more pulled down.

5 0
3 years ago
The most energy-efficient way to send a spacecraft to the Moon is to boost its speed while it is in circular orbit about the Ear
jeyben [28]

Answer:

98.33 %

Explanation:

On an elliptical orbit, angular momentum will be conserved .

Angular momentum = I ω = mvR

So mv₁R₁ = mv₂R₂

= v₁R₁ = v₂R₂

where v₁ is velocity and R₁ radius in low orbit (perigee)and v₂ and R₂ is velocity and radius in high orbit ( apogee ).

Here R₁ = Radius of the earth , R₂ is distance between moon and earth.

R₁ / R₂ = 1/60

v₁ /v₂ = R₂ / R₁  = 60

v₂ / v₁ = 1 / 60

1 - (v₂ / v₁ ) = 1 -( 1 / 60)

(v₁ -v₂)/v₁ = ( 60-1 )/60

(v₁ -v₂)/v₁ x 100 = 5900/60 = 98.33 %

5 0
4 years ago
The only way to slow down a moving object is to apply a net force to it.
salantis [7]
Hey there,

Answer: 

A, True

Hope this helps :D

<em>~Top☺
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4 0
3 years ago
Question 7 of 10
Lyrx [107]

Answer:

A. They can transfer energy through a vacuum

C. They vibrate in two directions that are perpendicular to each other

D. They radiate outward in all directions

Explanation:

8 0
3 years ago
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