Answer:
691.13 nm
Explanation:
d = width of the slit = 0.11 x 10⁻³ m
θ = angle of diffraction pattern = 0.72° degree
λ = wavelength of the light = ?
m = order = 2 (since second minimum)
for the second minimum diffraction pattern we use the equation
d Sinθ = m λ
Inserting the values
(0.11 x 10⁻³) Sin0.72 = (2) λ
λ = 691.13 x 10⁻⁹ m
λ = 691.13 nm
Answer:
1.925 μC
Explanation:
Charge: This can be defined as the product of the capacitance of a capacitor and the voltage. The S.I unit of charge is Coulombs (C)
The formula for the charge stored in a capacitor is given as,
Q = CV ................... Equation 1
Where Q = charge, C = Capacitor, V = Voltage.
Note: 1 μF = 10⁻⁶ F
Given: C = 0.55 μF = 0.55×10⁻⁶ F, V = 3.5 V.
Substitute into equation 1
Q = 0.55×10⁻⁶×3.5
Q = 1.925×10⁻⁶ C.
Q = 1.925 μC
Hence the charge on the plate = 1.925 μC
The gravitational attraction between two planets is 4905.95 N
<h3>What is gravitational attraction?</h3>
When two objects with masses are placed at a distance, there will an attractive force acting between them.
According to the Newton's law of gravitation, gravitational force is
F = Gm₁m₂ /r²
where r is the distance between the masses m₁ and m₂ and G is the gravitational constant G = 6.67 x 10⁻¹¹ N-m²/kg²
Substitute the values into the expression, we get
F = 6.67 x 10⁻¹¹ x 2.25 x 10²⁰ x 6.20 x 10¹⁸ / (435,500 x 1000)²
F= 4905.95 N
Thus, the gravitational attraction between two planets is 4905.95 N.
Learn more about gravitational attraction.
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Answer:
Straight line in a transverse wave represents the mean position of oscillating energy parameter at which the instantaneous amplitude is zero.
Explanation:
- A transverse wave is one in which the direction of propagation is perpendicular to the direction of oscillating energy vector.
- The transverse wave having a horizontal straight line represents the line of zero amplitude of oscillation.
- <em>When in graphical representation the curve intercepts this horizontal line then the amplitude of the oscillation and the phase of the wave becomes whole number multiple of 2π and as we know that the periodic oscillations are represented as a sinusoidal function which leads the amplitude to zero.</em>
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Answer:
(a) The least time required for the rotation is 50 seconds
(b) The corresponding value of α₁ is 1.6 rad/s²
Explanation: Please see the attachments below
