1. The domain of the function given in the problem are all those values for which the function that is in the denomiantor is different from zero, because the division by 0 is not allowed.

2. You can make the denominator equal to zero and solve it, as you can see below:

$x^{3}-2x^{2}+x=0\\x(x^{2}-2x+1)=0\\x(x-1)(x-1)=0\\x=0\\x=1$

3. Therefore, the domain is:

(-∞,0)U(0,1)U(1,∞)

8 0

3 years ago

Read 2 more answers

Need help ... ??????????

DochEvi [55]

Answer:

what is the quistion

Step-by-step explanation:

6 0

3 years ago

Which scatterplot demonstrates a non-linear relationship between x and y?

stiks02 [169]

Answer:

D, or the bottom right.

Step-by-step explanation:

8 0

3 years ago

Find the mean of the following,-6,-10,-4,8,9,-2,5,6.

andre [41]

$mean = \frac{sum \: of \: all \: observations}{number \: of \: observations} \\ = > mean = \frac{( - 6) + ( - 10) + ( - 4) + 8 + 9 + ( - 2) + 5 + 6}{8} \\ = > mean = \frac{6}{8} \\ = > mean = 0.75$

This is the answer.

8 0

3 years ago