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Solnce55 [7]
3 years ago
15

Which reaction would cause an increase in entropy? A. SO2Cl2(g) SO2(g) + Cl2(g) B. PCl3(g) + Cl2(g) PCl5(g) C. 2CO(g) + O2(g) 2C

O2(g) D. C2H2(g) + H2(g) C2H4(g)
Chemistry
2 answers:
IrinaVladis [17]3 years ago
8 0
A. SO2Cl2(g) --> SO2(g) + Cl2(g) 
<span>1 mole of SOCl2 becomes 1 mole SO2 and 1 mole Cl2 </span>
<span>1 mole --> 2 moles </span>
<span>entropy increases </span>

Nady [450]3 years ago
6 0

Answer: A) SO_2Cl_2(g)\rightarrow SO_2(g)+Cl_2(g)

Explanation: Entropy is the measure of randomness or disorder of a system. If a system moves from an ordered arrangement to a disordered arrangement, the entropy is said to decrease and vice versa.

A) SO_2Cl_2(g)\rightarrow SO_2(g)+Cl_2(g)

1 mole of gaseous reactant is converting to 2 gaseous products, thus the entropy increases.

B) PCl_3(g)+Cl_2(g)\rightarrow PCl_5(g)

2 moles of gaseous reactants are converting to 1 gaseous products, thus the entropy decreases.

C) 2CO(g)+O_2(g)\rightarrow 2CO_2(g)

3 moles of gaseous reactants are converting to 1 gaseous product, thus the entropy decreases.

D. C_2H_2(g)+H_2(g)\rightarrow C_2H_4(g)

2 moles of gaseous reactants are converting to 1 gaseous product, thus the entropy decreases.

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What will be the volume occupied by 2.5 moles of nitrogen gas exerting 1.75 atm of pressure at 475K?
Marina86 [1]

Answer:

THE VOLUME OF THE NITROGEN GAS AT 2.5  MOLES , 1.75 ATM AND 475 K IS 55.64 L

Explanation:

Using the ideal gas equation

PV = nRT

P = 1.75 atm

n = 2.5 moles

T = 475 K

R = 0.082 L atm/mol K

V = unknown

Substituting the variables into the equation we have:

V = nRT / P

V = 2.5 * 0.082 * 475 / 1.75

V = 97.375 / 1.75

V = 55.64 L

The volume of the 2.5 moles of nitrogen gas exerted by 1.75 atm at 475 K is 55.64 L

6 0
3 years ago
What is an open-loop system?
Naddika [18.5K]

A.  A group of related objects that do not send out or receive feedback and cannot modify themselves

Explanation:

An open-loop system is a a group of related objects or systems that cannot send out or receive feedback and modify themselves.

  • It is a non-feedback system.
  • In this system, the output control system has no effect on whatever input that is fed into the system.
  • Output and input in such systems are independent of one another.
  • The input and output has no control whatever on each other.

learn more:

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5 0
3 years ago
Enter your answer in the provided box. From the data below, calculate the total heat (in J) needed to convert 0.304 mol of gaseo
diamong [38]

Answer:

-35,281.5 J

Explanation:

To convert the gaseous ethanol to liquid ethanol, three steps will occur. First, it will lose heat and the temperature will decrease until its boiling point, so from 300.0°C to 78.5°C. Thus, more heat will be lost, but now, with the temperature constant, so the gas will be converted to liquid. And then, the liquid will lose heat to decrease the temperature from 78.5°C to 25.0°C.

The total heat loss is the sum of the heats of each step. Because the heat is being removed from the system, it's negative. The first and last step occurs with a change in temperature, and so the heat is calculated by:

Q = m*c*ΔT

Where m is the mass, c is the specific heat of the gas (first step) or liquid (last step), and ΔT the temperature variation (final - initial). The mass of ethanol is the molar mass 46.07 g/mol multiplied by the number of moles, so:

m = 46.07 * 0.304 = 14.00 g

The second step occurs without a change in temperature, and the heat is then:

Q = -n*ΔH°vap

Where n is the number of moles, ΔH°vap is the heat of vaporization, and the minus signal indicates that the heat is being lost. Then, the heat of each step is:

Q1 = 14.00*1.43*(78.5 - 300,0) = -4434.43 J

Q2 = -0.304*40.5 = -12.312 kJ = -12312 J

Q3 = 14.00*2.45*(25.0 - 78.5) = -1835.05 J

Q = Q1 + Q2 + Q3

Q = -35,281.5 J

5 0
3 years ago
What is the term for an object's strength of motion?
Andrei [34K]

I'm pretty sure its momentum

3 0
3 years ago
A 5-kg quantity of radioactive isotope decays to 2 kg after 10 years. Find the decay constant of the isotope.k = _____
Dvinal [7]

Answer:

k = -0.09165 years^(-1)

Explanation:

The exponential decay model of a radioactive isotope is generally given as;

A(t) = A_o(e^(kt))

Where;

A_o is quantity of isotope before decay, k is decay constant and A(t) is quantity after t years

We are given;

A_o = 5 kg

A(10) = 2kg

t = 10 years

Thus;

A(10) = 2 = 5(e^(10k))

Thus;

2 = 5(e^(10k))

2/5 = (e^(10k))

0.4 = (e^(10k))

In 0.4 = 10k

-0.9164 = 10k

k = -0.9164/10

k = -0.09165 years^(-1)

7 0
2 years ago
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