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Studentka2010 [4]
2 years ago
8

Of the following substances, an aqueous solution of ________ will form basic solutions. nh4cl cu(no3)2 k2co3 naf a) k2co3, nh4cl

b) naf only c) nh4cl only d) naf, k2co3 e) nh4cl, cu(no3)2
Chemistry
1 answer:
Andrew [12]2 years ago
6 0

The correct option is (a) NaHS, KHCO3 and NaF

NaHS, KHCO3 and NaF will form an aqueous solution of form basic.

<h3>What is aqueous solution?</h3>

A solution in which water serves as the solvent is called an aqueous solution. The most common way to display it in chemical equations is by adding to the appropriate chemical formula. For instance, the symbol for a solution of table salt, or sodium chloride, in water is Na+ + Cl.

To learn more about aqueous solution visit:

brainly.com/question/14097392

#SPJ4

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3 years ago
A chunk of tin weighing 18.5 grams and originally at 97.38 °C is dropped into an insulated cup containing 75.7 grams of water at
weqwewe [10]

Answer:

22.44°C will be the final temperature of the water.

Explanation:

Heat lost by tin will be equal to heat gained by the water

-Q_1=Q_2

Mass of tin = m_1=18.5 g

Specific heat capacity of tin = c_1=0.21 J/g^oC

Initial temperature of the tin = T_1=97.38^oC

Final temperature = T_2=T

Q_1=m_1c_1\times (T-T_1)

Mass of water= m_2=75.7 g

Specific heat capacity of water= c_2=4.184 J/g^oC

Initial temperature of the water = T_3=21.52^oC

Final temperature of water = T_2=T

Q_2=m_2c_2\times (T-T_3)

-Q_1=Q_2

-(m_1c_1\times (T-T_1))=m_2c_2\times (T-T_3)

On substituting all values:

-(18.5 g\times 0.21 J/g^oC\times (T-97.38^oC))=75.7 g\times 4.184 J/g^oC\times (T-21.52 ^oC)

we get, T = 22.44°C

22.44°C will be the final temperature of the water.

5 0
3 years ago
Types of atoms. The basic unit of matter. Pure substance is what?
ivanzaharov [21]

Solids, liquids, gases, and plasma are all matter. When all atoms that make up a substance are the same, then that substance is an element. Elements made of only one kind of atom. Because of this, elements are called "pure" substances.

hope this helps :)

7 0
3 years ago
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The following substances are commonly found in commercial antiacids. Write the acid/base reaction resulting from the The followi
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B.Mg(OH)2 (the active ingredient in milk of magnesia)

3 0
3 years ago
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Using the Rydberg formula, calculate the initial energy level when an electron in a hydrogen atom transitions into n= 2 and emit
EleoNora [17]

Answer:

1

Explanation:

Using the Rydberg formula as:

\frac {1}{\lambda}=R_H\times Z^2\times (\frac {1}{n_{1}^2}-\frac {1}{n_{2}^2})

where,

λ is wavelength of photon

R = Rydberg's constant (1.097 × 10⁷ m⁻¹)

Z = atomic number of atom

n₁ is the initial final level and n₂ is the final energy level

For Hydrogen atom, Z= 1

n₂ = 2

Wavelength = 410.1 nm

Also,

1 nm = 10⁻⁹ m

So,

Wavelength = 410.1 × 10⁻⁹ m

Applying in the formula as:

\frac {1}{410.1\times 10^{-9}}=1.097\times 10^7\times 1^2\times (\frac {1}{n_{1}^2}-\frac {1}{2^2})

Solving for n₁ , we get

n₁ ≅ 1

3 0
3 years ago
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