1.1 moles of C10H8 is the limiting reagent in the reaction between reaction C10H8 and O2
.
C10H8 + 12O2 ----> 10CO2 + 4H2O
C10H8 is the limiting reagent since 1.1 moles of C10H8 is totally consumed during the reaction
Answer:
Groups 1, 2, 13-18
Explanation:
The periodic table is divided into two broad categories: Main Group Elements and Transition Metals. The Main Group Elements include the alkali metals, alkaline earth metals, halogens, noble gases, and any groups not mentioned (see the answer).
Answer:
Explanation:
This means that as the equipotential lines are spaced closer and closer together, the electric field is stronger and stronger. ... This means that if the field is not doing any work on the particle as it moves, then the direction of the field's force must be perpendicular to the direction of the particle's motion.
Answer:
13.45 grams of NaCl will be produced
Explanation:
Given:
Mass of CuCl2 = 15 grams
Molar mass of CuCl2 = 134.5 g/mol
Mass of Na(NO3) = 20grams
Molar mass of Na(NO3) = 85 g/mol
To find:
Amount of Sodium chloride produced = ?
Solution:
<u>No of moles of CuCl2 = 15/134.5 = 0.11 moles</u>
<u>No of moles of Na(NO3) = </u><u>2</u><u>0</u><u>/</u><u>8</u><u>5</u><u> </u><u>=</u><u> </u><u>0.23 moles,</u>
<em><u>1CuCl2 + 2Na(NO3) --> 1Cu(NO3)2 + 2NaCl</u></em>
from the reaction, 1 mole of copper chloride reacts with 2 mole of NaNO3 to produce 2 moles of sodium chloride.
Hence, 0.11 mole of copper chloride will react with 0.23 mole of NaNO3 to produce 0.23 moles of sodium chloride.
Mass of 0.23 moles of NaCl = 0.23 × M.M of NaCl
<em><u>(Molar mass of NaCl = 58.5)</u></em>
Mass of 0.23 moles of NaCl = 0.23 × 58.5 = 13.45 grams
<em><u>Thanks</u></em><em><u> </u></em><em><u>for</u></em><em><u> </u></em><em><u>joining</u></em><em><u> </u></em><em><u>brainly</u></em><em><u> </u></em><em><u>community</u></em><em><u>.</u></em>
<span>solubility and flammability are both properties of chemical properties</span>