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Lina20 [59]
3 years ago
8

Write a sentence using the term atomic theory

Chemistry
2 answers:
ivolga24 [154]3 years ago
8 0
Atomic theory is the theory that all matter is made up of tiny invisible particles
ahrayia [7]3 years ago
5 0
Atomic Theory can be used in two subjects, physics and chemistry.
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The diagram below shows the different phase transitions that occur in matter.
Nimfa-mama [501]

The arrow that represents the transition in which dew is formed would be arrow 4.

<h3>How is dew formed?</h3>

Dew is formed by condensation. Condensation, in itself, involves a transition from a gas phase to a liquid phase.

From the diagram, the arrow that represents a transition from gas to liquid is arrow 4.

Thus, the arrow that represents the transition that leads to the formation of dew would be arrow 4.

More on dew formation can be found here: brainly.com/question/23169635

#SPJ1

3 0
1 year ago
Read 2 more answers
If a weak acid is 25 deprotonated at ph 4 what would the pka be
elena-s [515]

4.48

pH=pKa+log([A-/HA])

25% deprotonated tells us that A- is .25 and that the rest (75% is protonated) thats .75.

4 = pKa + log \frac{.25}{.75}

4 - log \frac{.25}{.75}  = pKa

4.48=pKa

6 0
3 years ago
Approximately _____ elements occur naturally on earth.
boyakko [2]
90 elements occur naturally on earth.
5 0
3 years ago
Read 2 more answers
25 g of a chemical is dissolved in 75 g of water. What is the percent by mass concentration of this chemical
Zanzabum

Answer:

300

Explanation:

4 0
2 years ago
A metal sample weighing 129.00 grams and at a temperature of 97.8 degrees Celsius was placed in 45.00 grams of water in a calori
Nitella [24]

Answer : The specific heat of metal is 0.481J/g^oC.

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of metal = ?

c_2 = specific heat of water = 4.184J/g^oC

m_1 = mass of metal = 129.00 g

m_2 = mass of water = 45.00 g

T_f = final temperature = 39.6^oC

T_1 = initial temperature of metal = 97.8^oC

T_2 = initial temperature of water = 20.4^oC

Now put all the given values in the above formula, we get

129.00g\times c_1\times (39.6-97.8)^oC=-45.00g\times 4.184J/g^oC\times (39.6-20.4)^oC

c_1=0.481J/g^oC

Therefore, the specific heat of metal is 0.481J/g^oC.

4 0
3 years ago
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