Answer:
The formula i use is called, Product over Sum. Which means it is figured by their multiplied resistances divided by their sum. It is applied by pairs of known resistances. Starting with 20 and 30 Ohms, 600 is divided by 50. Using a quick mental calculation, the first pair has a resistance of 12 Ohms. Then, do that with 12 Ohms and 10 Ohms. 120 Ohms divided by 22. The answer is, about 5.5 Ohms. By this interesting development, we are reminded that resistances in parallel are effectively never more than the least one.
The students decide to assemble a convenient experiment and will run one amp through them all in parallel and measure their voltage. Watching the Amperage gauge on their teacher’s power supply. As one begins to turn it up to an Amp, another is watching its voltage till an Amp is perfectly applied. But as they carefully do that, watching the Amp gauge, another screams, their 10 Ohm resistor turns black and smokes as they were only pumping out 2 or 3 tenths of an Amp. What happened? What did they need, to make this simple experiment not so embarass-king?
Buy room air freshener?
V=D/T
V=107 m / 27 s - divide distance by time
V= 4 m/s - because when we round 3.9629 in the nearest 10th we will get 4.
Hope this helps
The concept required to solve this problem is hydrostatic pressure. From the theory and assuming that the density of water on that planet is equal to that of the earth we can mathematically define the pressure as
Where,
= Density
h = Height
g = Gravitational acceleration
Rearranging the equation based on gravity
The mathematical problem gives us values such as:
Replacing we have,
Therefore the gravitational acceleration on the planet's surface is
The first choice is the true statement.
<h2>Force = 49 N</h2>
Explanation:
The gravitational force of attraction on the surface of earth F = G M m/R²
Here G = gravitational constant = 6.67 x 10⁻¹¹
M = mass of the earth and m = mass of the body on the surface of earth .
R = radius of earth
In this question
mass of earth = 6 x 10²⁴ kg and its radius = 6 x 10⁶ m
The values are substituted in the above equation
F = 6.67 x 10⁻¹¹ x 6 x 10²⁴ x 5 / ( 6 x 10⁶ )² = 49 N
The mass will be attracted by 49 N of force .