u = 0.077
Explanation:
Work done by friction is
Wf = ∆KE + ∆PE
-umgx = ∆KE,. ∆PE =0 (level ice surface)
-umgx = KEf - KEi = -(1/2)mv^2
Solving for u,
u = v^2/2gx
= (12 m/s)^2/2(9.8 m/s^2)(95 m)
= 0.077
Answer:
E
Explanation:
F seems more like a corona
Strength of the magnetic field: C) 20 T
Explanation:
When a conductive wire moves in a region with magnetic field, an electromotive force is induced in the wire due to the phenomenon of electromagnetic induction.
If the wire moves perpendicular to the field, the magnitude of the induced emf in the wire is given by

where
B is the strength of the magnetic field
L is the length of the wire
v is the speed of the wire
For the wire in this problem, we have:
is the emf induced in the wire
v = 3.0 m/s is the speed of the wire
L = 0.20 m is its length
Solving for B, we find the strength of the magnetic field:

Learn more about magnetic fields:
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Answer:
The velocity
of the cart with respect to the ground is

if we consider North the positive y-direction and East the positive x-direction.
Explanation:
We have for relative motion the following expression:

Where
is the velocity of the cart with respect to the ground,
is the velocity of the cart with respect to the plane and
is the velocity of the plane with respect to the ground.
We find that:


Thus: