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3 years ago

Do objects tend to stay moving because of a force called Interia

1 answer:

6 0

The first law of Newton’s law state an object in motion will stay in motion and an object at rest will stay at rest unless acted upon with an outside force. Other know as the law of inertia so yes it does

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Physics!!! please help D:

Ugo [173]

Answer: A

Explanation: isotopes of the same thing element have the same number of protons in the nucleus but differ in the number of neutrons.

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2 years ago

Blank is a measure of the percentage of water vapor in the air in a particular area

zaharov [31]

Answer:

Relative humidity is a measure of the percentage of water vapor in the air in a particular area

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2 years ago

You are on a boat in a fog and know there are cliffs ahead of you somewhere, but you cannot see them. you use your fog horn to s

ELEN [110]

The distance of the cliff from where you are is determined as 3,430 m.

<h3>Distance of the cliff</h3>

Apply the formula for echo.

v = 2d/t

where;

v is speed of sound at 20 ⁰C = 343 m/s
d is distance = ?
t is time = 20 s

2d = vt

d = vt/2

d = (343 x 20)/2

d = 3430 m

Thus, the distance of the cliff from where you are is determined as 3,430 m.

Learn more about echo here: brainly.com/question/14090821

#SPJ1

3 0

1 year ago

Why does the sun generally appear to rise in the east, move across the sky, and set in the west each day?

Aleksandr [31]

Answer:

1 is the answer

Explanation:

6 0

3 years ago

Read 2 more answers

A ball is moving with velocity 5 m/s in a direction which makes an angle of 30° with horizontal (i.e. with positive x-direction)

klasskru [66]

Answer:

Explanation:

(a)

From the given information:

The initial velocity $v_1$ = 5 m/s

The direction of the angle θ = 30°

Therefore, the component along the x-axis = $v_1 \ cos \ \theta$

$v_{1 \ x } = 5 \ cos \ 30^0$

$v_{1x} = 4.33 \ m/s$

The component along the y-axis = $v_2 { \ sin \ \theta}$

$v_{1 \ y } = 5 \ sin \ 30^0$

$v_{1 \ y } = 2.5 \ m/s$

To find the final velocity( reflected velocity)

using the same magnitude $v_2 = 5 \ m/s$

The angle from the x-axis can be $\theta_r = 90^0+60^0$

= 150°

Thus, the component along the x-axis = $v_2 \ cos \theta _r$

$v_{2x} = - 0.433 \ m/s$

The component along the y-axis = $v_2 \ sin \theta_r$

$v_{2y} = 5 \ sin \ 150^0$

$v_{2y} = 2.5 \ m/s$

(b)

The velocity $v_1$ can be written as in vector form.

$v_1 ^{\to} = v_1 x \hat {i} + v_1 y \hat {j}$

$v_1 ^{\to} =4.33 \ \hat {i} + 2.5 \ \hat {j}$ ---- (1)

The reflected velocity in vector form can be computed as:

$v_2 ^{\to} = v_2 x \hat {i} + v_2 y \hat {j}$

$v_2 ^{\to} =-4.33 \ \hat {i} + 2.5 \ \hat {j}$ --- (2)

The change in velocity = $v_2 ^{\to} - v_1 ^{\to}$

$\Delta v ^{\to} = - 4.33 \hat i + 2.5 \hat j - 4.33 \hat i - 2.5 \hat j$

$\Delta v ^{\to} = - 8.66 \hat { i }$

(c)

The magnitude of change in velocity = $| \Delta V |$

$| \Delta V |$ = 8.66 m/s

6 0

2 years ago