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liq [111]
3 years ago
7

The wavelength of a wave is 2) A) the distance between two adjacent peaks of the wave. B) equal to the speed of the wave times t

he wave's frequency. C) the distance between a peak of the wave and the next trough. D) how strong the wave is. E) the distance between where the wave is emitted and where it is absorbed.
Physics
1 answer:
Anton [14]3 years ago
8 0

Answer:

Wavelength = the distance between two adjacent peaks of the wave.

Explanation:

The wavelength of a wave is defined as the distance between two adjacent peaks of the wave or it is defined as the distance between two consecutive crests and troughs. It is denoted by \lambda. Its SI unit is meters.

The relation between the frequency and the wavelength is given by :

v=\nu\times \lambda

Where

v is the speed

So, the correct option is (a). " the distance between two adjacent peaks of the wave".

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Yuliya22 [10]

Answer:

12 km/h

Explanation:

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Pick a point on the graph for Ian and plug in values.

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4 years ago
At time t = 0 s, a wheel has an angular displacement of zero radians and an angular velocity of +26 rad/s. The wheel has a const
Alex777 [14]

Answer:

t= 25.04 s

Explanation:

Given  that

Initial angular speed ,ωi= 26 rad/s

Angular acceleration ,α=0.43 rad/s²

We know that kinetic energy of the wheel given as

KE=\dfrac{1}{2}I\omega^2

I=Mass monent of inertia

ω=Angular speed

If kinetic energy is two time then the final angular speed

\omega_f=\sqrt{2}\ \omega_i

We know that

\omega_f = \omega_i + \alpha\ t

\sqrt{2}\ \omega_i= \omega_i +0.43\times t

t= 25.04 s

After 25.04 s then kinetic energy will become two times of the initial kinetic energy.

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On my bike, I was able to travel 40 miles in one hour. From this information, we can determine the bikes
avanturin [10]

Answer:

Explanations :

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3 years ago
What voltage is needed to create a current of 43 mA in a circuit containing only a 1.3-μF capacitor, when the frequency is 3.9 k
Leviafan [203]

Answer:

1.35 V

Explanation:

Given:

Capacitance of the capacitor (C) = 1.3 μF = 1.3\times 10^{-6}\ F\ \ [1\mu F=10^{-6}\ F]

Frequency (f) = 3.9 kHz= 3.9 × 1000 Hz = 3900 Hz [1 kHz = 1000 Hz]

Current flowing in the circuit (I) = 43 mA = 0.043 A [1 mA = 0.001 A]

Now, as only capacitor is there in the circuit, the impedance of the circuit is equal to the reactance of the capacitor.

So, Z=X_C

The reactance of the capacitor is given as:

X_C=\frac{1}{2\pi fC}

Plug in the values given and solve for X_C. This gives,

X_C=\frac{1}{2\pi\times 3900\times 1.3\times 10^{-6}}\\\\X_C=31.39\ \Omega

Therefore, the impedance is, Z=31.39\ \Omega

Now, the voltage needed to create the given current is obtained using the formula from Ohm's law and is given as:

V=IZ\\\\V=(0.043\ A)(31.39\ \Omega)\\\\V=1.35\ V

Therefore, the voltage needed to create a current of 43 mA is 1.35 V.

3 0
3 years ago
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