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Kisachek [45]
3 years ago
15

What is the final velocity of a car that starts at 22 m/s and accelerates at 3.78 m/s for distance of 45 m

Physics
1 answer:
Pepsi [2]3 years ago
5 0

v^2 = v0^2 +2ad v^2 = 22^2 + 2*3.78*45 = 824.2 v= √824.2 = 28.7 m/s

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