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Hitman42 [59]
2 years ago
6

A runner is at rest at the starting line of a race. She accelerates at 3.3m/s/s. What is her position after 7.5s? Round your ans

wer to the nearest tenth of a meter.
Physics
1 answer:
natulia [17]2 years ago
3 0

Answer:

sorry ‍♂️I don't know the answer

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What is a direct result of having greenhouse gases in the atmosphere?
Shalnov [3]

Answer:

Well this is tough. I'm not sure but you are smart and can push through it. YOU DONT need the someone telling you the answer when it is inside you.

hope this helps p

3 0
2 years ago
Read 2 more answers
how do you find work when only given the angle a sled is pulled, the mass, the coefficent of kinetic friction and distance
Sergio039 [100]

Answer:

W = F * s    

Work done equals applied force * distance traveled

Apparent weight = M g (1 - sin θ)     since some of applied force will lighten sled

μ = coefficient of kinetic friction

F cos θ = force applied to motion of sled

s = distance traveled

[μ M g (1 - sin θ)] cos θ * s = work done in moving sled

Note that F = μ M g    if applied force is in the horizontal direction

8 0
1 year ago
The aurora is caused when electrons and protons, moving in the earth’s magnetic field of ≈5.0×10−5T, collide with molecules of t
ollegr [7]

Answer:

8.79*10^6 rad/s

Explanation:

To find the frequency of the circular orbit for an electron you use the following expression, for the radius of the trajectory of an electron, that travels trough a constant magnetic field:

r=\frac{mv}{qB}         (1)

r: radius of the trajectory

m: mass of the electron = 9.1*10^-31 kg

v: speed of the electron = 1.0*10^6 m/s

q: charge of the electron = 1.6*10^-19 C

B: magnitude of the magnetic field = 5.0*10^-5 T

You use the fact that the angular frequency in a circular motion is given by:

\omega=\frac{v}{r}

Then, you solve the equation (1) in order to obtain v/r:

\frac{v}{r}=\omega=\frac{qB}{m}

Finally, you replace the values of the parameters:

\omega=\frac{(1.6*10^{-19}C)(5.0*10^{-5}T)}{9.1*10^{-31}kg}\\\\\omega=8.79*10^6\frac{rad}{s}

hence, the angular frequency is 8.79*10^6 rad/s

The frequency is:

f=2\pi \omega=5.5*10^7Hz

5 0
2 years ago
Describe an experiment to show that pressure increases with the decrease in the area of surface
cluponka [151]
Answer:
press a baloon against one pin it bursts
but now arrange lot of pins parallel closely to each other if u press a baloon against them it does not burst hope this helps u
7 0
2 years ago
How many ways can motion change
meriva

Answer:

There are four main ways of doing that :-

  • Velocity
  • Acceleration
  • Momentum
  • Kinetic energy

Hope it helps!

7 0
3 years ago
Read 2 more answers
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