Answer:
Momentum of block B after collision =![-50\ kg\ ms^{-1}](https://tex.z-dn.net/?f=-50%5C%20kg%5C%20ms%5E%7B-1%7D%20)
Explanation:
Given
Before collision:
Momentum of block A =
= ![-100\ kg\ ms^{-1}](https://tex.z-dn.net/?f=-100%5C%20kg%5C%20ms%5E%7B-1%7D)
Momentum of block B =
= ![-150\ kg\ ms^{-1}](https://tex.z-dn.net/?f=-150%5C%20kg%5C%20ms%5E%7B-1%7D)
After collision:
Momentum of block A =
= ![-200\ kg\ ms^{-1}](https://tex.z-dn.net/?f=-200%5C%20kg%5C%20ms%5E%7B-1%7D)
Applying law of conservation of momentum to find momentum of block B after collision
.
![p_{A1}+p_{B1}=p_{A2}+p_{B2}](https://tex.z-dn.net/?f=p_%7BA1%7D%2Bp_%7BB1%7D%3Dp_%7BA2%7D%2Bp_%7BB2%7D)
Plugging in the given values and simplifying.
![-100-150=-200+p_{B2}](https://tex.z-dn.net/?f=-100-150%3D-200%2Bp_%7BB2%7D)
![-250=-200+p_{B2}](https://tex.z-dn.net/?f=-250%3D-200%2Bp_%7BB2%7D)
Adding 200 to both sides.
![200-250=-200+p_{B2}+200](https://tex.z-dn.net/?f=200-250%3D-200%2Bp_%7BB2%7D%2B200)
![-50=p_{B2}](https://tex.z-dn.net/?f=-50%3Dp_%7BB2%7D)
∴ ![p_{B2}=-50\ kg\ ms^{-1}](https://tex.z-dn.net/?f=p_%7BB2%7D%3D-50%5C%20kg%5C%20ms%5E%7B-1%7D%20)
Momentum of block B after collision =![-50\ kg\ ms^{-1}](https://tex.z-dn.net/?f=-50%5C%20kg%5C%20ms%5E%7B-1%7D%20)
Answer: B. 15.2s
Explanation: 600/39.5 = about 15.2
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Answer: I believe the answer is C. Higher Volume.
Explanation: I apologize if I am incorrect.
Answer:
Explanation:
Magnetic field due to a long current carrying conductor
μ₀ / 4π x 2i / r ( i = current , r = distance of point from wire )
= 10⁻⁷ x 2 x 120 / 6.4 ( i = 120 A , r = 6.4m )
= 37.5 x 10⁻⁷ T .
= 3. 75 X 10⁻⁶ T .
= 3.75 µT.
b )
The direction of this field will be horizontal hence it will affect magnetic needle.