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LuckyWell [14K]
3 years ago
6

Calculate the speed of an object having momentum 7.25 x 10^5 kg.m/s and mass 0.285 kg. Answer in units of m/s.

Physics
1 answer:
Olenka [21]3 years ago
3 0

Answer:

speed is 25.43 85 x 10^5  m/s

Explanation:

momentum = 7.25 x 10^5 kg.m/s

mass = 0.285 kg

to find out

speed

solution

we have given mass and momentum so

to find speed we apply here momentum formula that is

momentum = mass × speed   ...................1

put here all value and find speed

speed = momentum / mass

speed = 7.25 x 10^5 / 0.285

speed = 2543859.649

so speed is 25.43 85 x 10^5  m/s

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How many times did john glenn orbit the earth
galben [10]

Answer:

2 times

Explanation:

1st time on Feb. 20, 1962 at age 41

2nd time on Oct. 29, 1998 at age 77

8 0
3 years ago
Why does Quito, Equator has very little changes to the daylight hours<br> throughout the year?
marin [14]

Because of the position on the equator, the change in rotation of the Earth on its axis throughout the year doesn't affect it much. Unlike the poles, Quito is almost constantly in direct view of the sun. So, because of lack of change in rotation, the daylight hours are hardly varied as Quito is almost constantly in more or less the same spot in relation to the sun.

4 0
3 years ago
A boy throws a ball into the air at 10.2 m/s. Assuming that only gravity acts on the ball, how high does it rise, in m?
ozzi
Answer: 5.31 meters

Explanation: Use conservation of energy. Initial energy equals final energy. Initially, there is only kinetic energy (because height = 0 initially). At the end, kinetic energy equals 0 because at max height, there is max potential energy and the ball stops moving for a split second.

mgh = .5mv^2
Masses cancel out
gh = .5v^2
(9.8)(h) = .5(10.2^2)
Solve for h. h = 5.31 meters
5 0
3 years ago
A 912-kg car is being driven down a straight, level road at a constant speed of 31.5 m/s. When the driver sees a police cruiser
sergejj [24]

Answer:

786.6 N

Explanation:

mass of car, m = 912 kg

initial velocity of car, u = 31.5 m/s

final velocity of car, v = 24.6 m/ s

time, t = 8 s

Let a be the acceleration of the car

Use first equation of motion

v = u + a t

24.6 = 31.5 + a x 8

a = - 0.8625 m/s^2

Force, F = mass x acceleration

F = 912 x 0.8625

F = 786.6 N

Thus, the force on the car is 786.6 N.

8 0
3 years ago
I don't understand this question at all, can I please get some help?
beks73 [17]
V^2/R=180W
v=root 180R
4 0
3 years ago
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