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storchak [24]
3 years ago
5

How many molecules are in 4CO2

Chemistry
1 answer:
Novay_Z [31]3 years ago
4 0
4CO2 is 4 molecules of CO2. CO2 consists of one carbon atom and two oxygen atoms.

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With white light, a team measured a 0.7% percent change with 3.5g of plant matter in a one liter container. Convert
Strike441 [17]

moles CO₂ = 5.57.10⁻⁴

<h3>Further explanation   </h3>

A mole is a number of particles(atoms, molecules, ions)  in a substance

Can be formulated :

\tt mol=\dfrac{mass}{MW}

0.7% percent change with 3.5g of plant matter

mass :

\tt 0.7\%\times 3.5~g=0.0245~g

moles :

\tt moles=\dfrac{0.0245}{44}=0.000557=5.57.10^{-4}

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3 years ago
Explain why vegetables last longer in a fridge.
jeka57 [31]

It has to do with the releasing of ethylene, which speeds up the ripening process  

6 0
2 years ago
Read 2 more answers
Why is gunshot residue important for a forensic scientist? What are the potential complications with this type of evidence?
erik [133]
A residue from a gunshot is most likely gun powder, which tells you what kind of bullet was shot and the type of gun that was used to shoot the target/victim/person. Some complications may be that there is more than one gun or weapon which uses that residue, so it may be hard to pinpoint it and the bullet can't really tell you who it is unless there's DNA on the bullet, and the chemicals of the bullet may even destroy evidence.
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3 years ago
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When combined in the correct ratio hydrogen and oxygen atoms can form water as shown below
Dimas [21]

Answer:molecule of a compound

Explanation:

8 0
2 years ago
If 20.0 grams of Al is placed into a solution containg
meriva

Answer:

m H2(g) = 2.241 g H2(g)

Explanation:

  • 2Al(s) + 3H2SO4(aq) → Al2(SO4)3(aq) + 3 H2(g)

limit reagent:

∴ Mw Al = 26.982 g/mol

∴ Mw H2SO4 = 98.0785 g/mol

⇒ n Al = (20 g Al)×(mol/26.982 g) = 0.7412 mol Al

⇒ n H2SO4 = ( 115 g H2SO4 )×(mol/98.0785 g) = 1.173 mol H2SO4

⇒ n H2 = (0.7412 mol Al)×(3 mol H2/ 2 mol Al) = 1.112 mol H2

∴ Mw H2 = 2.016 g/mol

⇒ g H2 = (1.112 mol H2)×(2.016 g/mol) = 2.241 g H2

5 0
3 years ago
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