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koban [17]
3 years ago
11

The electric force between two charged vinyl balloons is 3.0 × 10-3 newtons. If the distance between them is 6.0 × 10-2 meters a

nd the charge of one vinyl balloon is 3.3 × 10-8 coulombs, what is the charge on the other vinyl balloon? (k = 9.0 × 109 newton·meter2/coulombs2)
A. 3.3 × 10-8 coulombs

B. 3.6 × 10-6 coulombs

C. 4.8 × 10-8 coulombs

D. 6.0 × 10-8 coulombs

E. 3.3 × 10-3 coulombs
Physics
2 answers:
LuckyWell [14K]3 years ago
6 0
We use the equation expressed as:

<span>F= k*Q*q/(r^2)
</span>
where k is equal to 9.0 × 109 newton·meter2/coulombs2, Q is the charge of one particle, q is the charge of the other particle and r is the distance between them.

3.0 × 10^-3 = 9.0 × 10^9( 3.3 × 10-8 coulombs ) q / (6.0 × 10-2)²
q = 3.3 × 10-8 coulombs
seraphim [82]3 years ago
3 0

Answer:

Charge on other vinyl balloon is, q_2=3.3\times 10^{-8}\ C

Explanation:

It is given that,

Electric force between two charged vinyl balloons, F=3\times 10^{-3}\ N

Distance between balloons, d=6\times 10^{-2}\ m

Charge on one vinyl balloon, q_1=3.3\times 10^{-8}\ C

We have to find the charge on another balloon. It can be calculated using the formula for electrostatic force. It is given by :

F=k\dfrac{q_1q_2}{r^2}

q_2=\dfrac{Fr^2}{kq_1}

q_2=\dfrac{3\times 10^{-3}\times (6\times 10^{-2})^2}{9\times 10^9\times 3.3\times 10^{-8}}          

q_2=3.3\times 10^{-8}\ C

Hence, the correct option is (A).                  

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