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True [87]
3 years ago
8

Does direction matter when determining distance? yes no

Physics
1 answer:
zloy xaker [14]3 years ago
6 0

Answer:

no

Explanation:

ans should be correct

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The speed of surface waves in water decreases as the water becomes shallower. Suppose waves travel across the surface of a lake
Elanso [62]

Answer:

The correct solution is "1.2 m".

Explanation:

The given values are:

Wavelength of waves,

λ = 1.5 m

Speed of waves on surface,

V = 2 m/sec

Speed of waves in water,

V₁ = 1.6 m/sec

As we know,

⇒  V=f\times \lambda

or,

⇒  f=\frac{V}{\lambda}

On substituting the values, we get

⇒      =\frac{2}{1.5}

⇒      =1.33 \ Hz

hence,

⇒  \lambda_1=\frac{V_1}{f}

On substituting the values, we get

⇒       =\frac{1.6}{1.33}

⇒       =1.2 \ m

7 0
3 years ago
Which phase comes after waxing crescent moon
12345 [234]

Answer:

new moon

Explanation:

6 0
3 years ago
What creates more pressure?Check all that apply A.Gas molecules moving more quickly B.More gas molecules C. Going to a higher al
Shkiper50 [21]
It's A.Gas molecules moving more quickly..... hope it helps you dear
7 0
3 years ago
How high does a rocket have to go above Earth's surface before its weight is half of what it is on Earth?
Contact [7]

Answer:

h=1.6\times 10^6\ m

Explanation:

As we know that the acceleration due to gravity decreases with height.

At certain height it will get to the half of its value on the surface of the earth.

As we know that the weight on the surface of the earth is given as:

w=m.g

where:

m = mass of the object

g = acceleration due to gravity of the substance

Since mass of the substance is constant so the variation is weight is possible only due to change in the acceleration due to gravity.

<u>We know that the variation of the acceleration due gravity with height is given as:</u>

g_{_h}=g\times (1-\frac{2h}{R} )

where:

g_{_h}= value to acceleration due to gravity at height h

g = acceleration due to gravity at the earth's surface

h = height of the object

R = radius of the earth = 6400\ km

according to question the weight becomes half, so,:

4.9=9.8\times (1-\frac{2h}{6400\times10^3} )

h=1.6\times 10^6\ m is the height a rocket has to go above Earth's surface before its weight is half of what it is on Earth.

4 0
3 years ago
How do you know when motion has occurred?
Masteriza [31]
An object in motion changes position

7 0
4 years ago
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