If all the stars in an elliptical galaxy traveled random directions in their orbits, the elliptical galaxy would be type
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Complete Question
A small metal sphere, carrying a net charge q1=−2μC, is held in a stationary position by insulating supports. A second small metal sphere, with a net charge of q2= -8μC and mass 1.50g, is projected toward q1. When the two spheres are 0.80m apart, q2 is moving toward q1 with speed 20ms−1. Assume that the two spheres can be treated as point charges. You can ignore the force of gravity.The speed of q2 when the spheres are 0.400m apart is.
Answer:
The value
Explanation:
From the question we are told that
The charge on the first sphere is
The charge on the second sphere is
The mass of the second charge is
The distance apart is
The speed of the second sphere is
Generally the total energy possessed by when and
are separated by
is mathematically represented
Here KE is the kinetic energy which is mathematically represented as
substituting value
And U is the potential energy which is mathematically represented as
substituting values
So
Generally the total energy possessed by when and
are separated by
is mathematically represented
Here is the kinetic energy which is mathematically represented as
substituting value
And is the potential energy which is mathematically represented as
substituting values
From the law of energy conservation
So
Answer:
Therefore the rate of corrosion 37.4 mpy and 0.952 mm/yr.
Explanation:
The corrosion rate is the rate of material remove.The formula for calculating CPR or corrosion penetration rate is
K= constant depends on the system of units used.
W= weight =485 g
D= density =7.9 g/cm³
A = exposed specimen area =100 in² =6.452 cm²
K=534 to give CPR in mpy
K=87.6 to give CPR in mm/yr
mpy
=37.4mpy
mm/yr
=0.952 mm/yr
Therefore the rate of corrosion 37.4 mpy and 0.952 mm/yr.