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klemol [59]
3 years ago
14

If all the stars in an elliptical galaxy traveled random directions in their orbits, the elliptical galaxy would be type

Physics
1 answer:
Lemur [1.5K]3 years ago
7 0

The answer would be E7. Galaxies categorized as E0 look to be nearly perfect, while those registered as E7 seem much extended than they are widespread. It is worth noting, though, that a galaxy's look is connected to how it lies on the sky when viewed from Earth. An E7 galaxy is very long and thin or the flattest of them all. 

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• A cable is suspended over a pulley. A 5.0 kg mass is attached to
Galina-37 [17]

Answer:

Tension= \frac{20g}{3}  (g=acceleration of gravity)

Explanation:

Given that,

A 5Kg and 10Kg are attached by a cable suspended over a pulley.

As 10Kg > 5Kg , the 10 kg mass accelerates down and the 5kg mass accelerates up, let it be a. Let the tension in the cable be T.

So, the equations of motion are

10g-T = 10a

T-5g=5a

Now adding them we get,

5g=15a

a=\frac{g}{3}

Substituting them back in the equation we get,

10g-10(\frac{g}{3} ) = T

T= \frac{20g}{3}

3 0
3 years ago
A ball is thrown with a speed of 20 m/s at an angle of 40o above the horizontal from the top of a 22-m tall building.
MrRissso [65]

Answer:

(a). The distance is  49.79 m.

(b). The speed of the ball is 24.39 m/s.

Explanation:

Given that,

Speed = 20 m/s

Angle = 40°

Height = 22 m

Time = 3.25 sec

(a). We need to calculate the distance

Using formula of distance

d=u\cos\theta\times t

Put the value into the formula

d=20\cos40\times3.25

d=49.79\ m

(b). We need to calculate the horizontal velocity

Using formula of velocity

v_{x}=u\cos\theta

Put the value into the formula

v_{x}=20\times\cos40

v_{x}=15.3\ m/s

We need to calculate the vertical velocity

Using equation of motion

v_{y}=u\sin\theta-gt

Put the value into the formula

v_{y}=20\sin40-9.8\times3.25

v_{y}=-19\ m/s

Negative sign shows the opposite direction.

We need to calculate the speed of ball

Using formula of speed

v=\sqrt{v_{x}^2+v_{y}^2}

v=\sqrt{(15.3)^2+(19)^2}

v=24.39\ m/s

Hence, (a). The distance is  49.79 m.

(b). The speed of the ball is 24.39 m/s.

4 0
3 years ago
F.r.e.e points :]]] ​
Colt1911 [192]
Ok? I don’t know what you want me to do though
4 0
3 years ago
Read 2 more answers
Which statement describes a digital signal?
hoa [83]

Answer:

"It is made of numbers" describes the digital signal.

Explanation:

The digital signal are the electrical signal which is translated into the pattern of bits. The digital signal are always discrete value in every sampling point. The conversion of the programming into the stream or the binary sequence like 0s and 1s. The digital signals never gets weaken over distance but the analog signal gets weakened or impair at distance. The digital signals are consists of one or two value, Timing graph are square waves.

4 0
3 years ago
Read 2 more answers
a mass on a spring vibrates in simple harmonic motion at an amplitude of 8.0 cm. if the mass of the object is 0.20kg and the spr
Reil [10]

Answer:

4.06 Hz

Explanation:

For simple harmonic motion, frequency is given by

f=\frac {1}{2\pi}\times \sqrt{\frac {k}{m}} where k is spring constant and m is the mass of the object.

Substituting 0.2 Kg for mass and 130 N/m for k then

f=\frac {1}{2\pi}\times \sqrt{\frac {130}{0.2}}=4.057670803\\f\approx 4.06 Hz

5 0
3 years ago
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