All categories

3 years ago

What are the results of habitat loss? choose the most likely outcome

Physics

2 answers:

s2008m [1.1K]3 years ago

6 0

Answer:

Explanation:

Seems the most reasonable to me

zmey [24]3 years ago

5 0

The Answer that makes the most sense is C.

You might be interested in

What force must the worker exert to get the box moving & what force must the worker exert to accelerate the box at 0.1 meter

photoshop1234 [79]

Since static friction is the minimum force required to just start the motion of a stationary object.

Here if we need to start an object from rest then we required F = 700 N

So for the first part of the above problem Force will be F = 700 N

Now if the box is already moving then we will have to use kinetic friction force between box and floor

now we can write the equation of net force as

$F - F_k = m*a$

here

$F_k = kinetic friction = 220 N$

$m = mass = 500 kg$

$a = acceleration = 0.1 m/s^2$

now we will have

$F - 220 = 500* 0.1$

$F = 220 + 50 = 270 N$

3 0

3 years ago

Air is a solution of 78% nitrogen, 21% oxygen and 1% other gases. Which part of this solution is the solvent?

Tom [10]

The answer is 78%. i got it right

6 0

3 years ago

Read 2 more answers

what is the ratio of ey,final, the maximum value of the y-component of the electric field immediately following the last polariz

OleMash [197]

That ratio is 2 .

<h3>What is ratio?</h3>

A ratio is the comparison of the two numbers bydivision.

Taking the first two outputs, or the -1/8 and -1/4, we can divide not the second one by the first one to find the

ratio:

-1/4-1/8

When dividing fractions, we multiply by the reciprocal:

-1/4x-8/1

To multiply fractions, multiply straight across:

(-1x-8)/(4x1) 8/4=2

To know more about ratio click-

brainly.com/question/25927869

#SPJ1

8 0

1 year ago

PLEASE HELP A student climbs to the top of a press box where the cameras are. He wonders how many meters he is off of the ground

Feliz [49]

The height of the rail on top of the press box where the ball was dropped from is 11.025 m.

The given parameters:

Time of motion of the ball, t = 1.5 s
Let the height of the rail = h

<h3>Maximum height of fall;</h3>

The maximum height through which the ball was dropped from is calculated by applying second equation of motion;

$h = v_0_y t + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\h = \frac{1}{2} (9.8) (1.5)^2\\\\h = 11.025 \ m$

Thus, the height of the rail on top of the press box where the ball was dropped from is 11.025 m.

Learn more about height of projectiles here: brainly.com/question/10008919

3 0

2 years ago

Two pulleys are fastened together to form an integral unit. At a certain instant, the indicated belt tensions act on the unit an

tresset_1 [31]

Answer:

α = $21.6 rad/s^2$

Explanation:

Applying the equations of motion to determine angular acceleration of the unit,

The sum of moments about O is equal to the product of angular acceleration and moment of inertia

∑Mo = Io*α

Taking the anticlockwise direction as positive moment,

= ( -(1150) + (1400) ) * (0.5 / 2) + ( (475) - (650) ) * (0.3 / 2) - F = Io*α

= 36.5 - (2.5 N.m) = $(m*ko^2)$ *α

NOTE: moment of inertia of the pulleys in this instance = $(m*ko^2)$

Hence, 33.75 = $25 * (0.25)^2$ * α

Solving, α = $21.6 rad/s^2$

8 0

3 years ago