Using Newton's second law of motion:
F=ma ; [ F = force (N: kgm/s^2);m= mass (kg); a = acceleration (m/s^2)
Given: Find: Formula: Solve for m:
F: 2500N mass:? F=ma Eq.1 m=F/a Eq. 2
a= 200m/s^2
Solution:
Using Eq.2
m= (2500 kgm/s^2)/ (200m/s^2) = 12.5 kg
Answer:
The value of bending stress on the pinion 35.38 M pa
Explanation:
Given data
m = 2 mm
Pressure angle = 20°
No. of teeth T = 17
Face width (b) = 20 mm
Speed N = 1650 rpm
Power = 1200 W
Diameter of the pinion gear
D = m T
D = 2 × 17
D = 34 mm
Velocity of the pinion gear
Form factor for the pinion gear is
Y = 0.303
Now
Force on gear tooth
F = 408.73 N
Now the bending stress is given by the formula
= 35.38 M pa
This is the value of bending stress on the pinion
Answer:
no
Explanation:
because if you test it they hit the ground at the same time.