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igomit [66]
3 years ago
11

A solution of 3 moles of carbon disulfide in 10 moles of ethyl acetate has a vapor pressure of 170 torr at 28°c. the vapor press

ure of pure carbon disulfide at 28°c is 390 torr. what is the vapor pressue of pure ethyl acetate at 28°c
Chemistry
1 answer:
nika2105 [10]3 years ago
7 0
Total pressure of solution = (P⁰carbon sulfide * X carbon sulfide) + (P⁰ethyl acetate * X ethyl acetate)
where:
P⁰ carbon sulfide is vapor pressure of pure Carbon sulfide
X carbon sulfide is mole fraction of carbon sulfide = (number of moles of carbon sulfide / total number of moles)
P⁰ ethyl acetate is vapor pressure of pure ethyl acetate
X ethyl acetate is mole fraction of ethyl acetate = (number of moles of ethyl acetate / total number of moles)

P soln = (P⁰CS₂ * X CS2) + (P⁰ethyl acetate * X ethyl acetate)
170 torr   = (390 torr * 3 / 13) + (P⁰ ethyl acetate * 10 / 13 )
P⁰ ethyl acetate = 104 torr


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Answer:

A =  0.75 ×10² KJ.

B = 3.9 ×10³ dg

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Explanation:

A =  7.5 ×10⁴ j to kilo joules

7.5 ×10⁴ / 1000 = 0.75 ×10² KJ.

Joule is the smaller unit while kilo joule is the larger unit. One kilo joule equals to the thousand joule that's why we will divide the given value by 1000 in order to convert into KJ.

B = 3.9 ×10⁵ mg to decigrams.

3.9 ×10⁵ / 100 = 3.9 ×10³ dg

Decigram is larger unit while milligram is smaller unit. One decigram is equal to the 100 milligram. In order to convert the given value into  decigram we have to divide the value by 100.

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2.21 ×10⁻⁴ ×10⁵ = 0.22 × 10² μl.

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4 0
3 years ago
What do the coefficients located before certain molecules in each chemical equation represent?
olga55 [171]
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4 0
2 years ago
The hormone thyroxine is secreted by the thyroid gland and has the formula: C15H17NO4I4. How many milligrams of Iodine can be ex
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6 0
3 years ago
Read 2 more answers
1. An oxide of chromium is found to have the following % composition: 68.4% Cr
abruzzese [7]

Answer:

Empirical formula is Cr₂O₃.

Explanation:

Given data:

Percentage of Cr = 68.4%

Percentage of O = 31.6%

Empirical formula = ?

Solution:

Number of gram atoms of Cr = 68.4 / 52 = 1.3 2

Number of gram atoms of O = 31.6 / 16 = 1.98

Atomic ratio:

                            Cr               :         O

                           1.32/1.32     :       1.98/1.32

                               1              :        1.5

Cr : O = 1 :  1.5

Cr : O = 2(1 : 1.5)

Empirical formula is Cr₂O₃.

6 0
3 years ago
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