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professor190 [17]
3 years ago
9

two small balls are suspended on parallel threads of the same length so that they touch each other in the vertical position. the

mass of the first ball is 0.4kg and the mass of the second ball is 200g. the first ball is deflected so that its centre of mass rises to a height of 6cm and it is then released. to what maximal height will the 200g ball rise if the collision is elastic?
Physics
1 answer:
Elden [556K]3 years ago
5 0

Answer: 12cm

Explanation:

Since first ball is raised to a height h1= 6cm, it gains a potential energy(PE1). On release, this PE1 is converted to kinetic Energy (KE1). This KE1 impact it energy on ball 2 ans it rise also. Since collision is elastic.

KE1 = KE2 ....> PE1 = PE2

m1 ×g × h1 = m2 × g× h2

h2 = m1×h1/m2

h2 = 0.4 × 0.06/0.2

h2 = 0.12m = 12cm

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A cell membrane is 0,0000005 m thick and has an electric potential difference between its surfaces of 0,10 V. What is the electr
Irina-Kira [14]

Answer:

Electric field in the membrane is given as

E = 2 \times 10^5 V/m

Explanation:

As we know that electric field in a region is related to its potential difference given by the formula

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here we know that

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5 0
4 years ago
Suppose that a simple pendulum consists of a small 60.0 g bob at the end of a cord of negligible mass. If the angle 0 between th
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Based on the mass of the bob and the angle between the cord and the vertical, the pendulum length is 0.50m.

The maximum kinetic energy can be found to be 9.42 x 10⁻⁴J.

<h3>What is the pendulum length?</h3>

This can be found as:

= g-force / w²

Solving gives:

= 9.8 / 4.43²

= 0.4998 m

= 0.50 m

<h3>What is the maximum kinetic energy?</h3>

This can be found as:

= 0.5 × m × w² × A²

Maximum kinetic energy is:

= 0.5 × 60 × 10⁻³ × (4.43 × 0.4998 x 0.08 rad)²

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Find out more on maximum kinetic energy at brainly.com/question/24690095.

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2 years ago
A 20 kg wagon is rolling to the right across a floor. A person attempts to catch and stop the crate and applies a force of 70 N,
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Answer:

1.736m/s²

Explanation:

According to Newton's second law;

\sum F_x = ma_x\\

Fm - Ff = ma_x\\ where;

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\mu is the coefficient of friction

m is the mass of the object

g is the acceleration due to gravity

a is the acceleration/deceleration

The equation becomes;

Fm - Ff = ma_x\\Fm - \mu mg = ma\\

Substitute the given parameters

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7 0
3 years ago
What is thermal energy defined as
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