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3 years ago

All objects, regardless of their mass, fall with the same rate of acceleration on

Physics

2 answers:

tamaranim1 [39]3 years ago

4 0

Answer:

A -TRUE

Explanation:

The mass, size, and shape of the object are not a factor in describing the motion of the object. So all objects, regardless of size or shape or weight, free fall with the same acceleration.

crimeas [40]3 years ago

3 0

True this is true because the acceleration is equal

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When a high-mass star explodes, which of the following is left over in the center?

il63 [147K]

I would say option D, it depends on the size of the star

8 0

3 years ago

Glycerin is poured into an open U-shaped tube until the height in both sides is 20cm. Ethyl alcohol is then poured into one arm

Liula [17]

Answer:

7.5 cm

Explanation:

In the figure we can see a sketch of the problem. We know that at the bottom of the U-shaped tube the pressure is equal in both branches. Defining $\rho_A:$ Ethyl alcohol density and $\rho_G:$ Glycerin density , we can write:

$\rho_A\times g \times h_1 + \rho_G \times g \times h_2 = \rho_G \times g \times h_3$

Simplifying:

$\rho_A\times h_1 = \rho_G \times (h_3 - h_2) (1)$

On the other hand:

$h_1 + h_2 = \Delta h + h_3$

Rearranging:

$h_1 - \Delta h = h_3 - h_2 (2)$

Replacing (2) in (1):

$\rho_A\times h_1 = \rho_G \times (h_1 - \Delta h)$

Rearranging:

$\frac{h_1 \times (\rho_A - \rho_G)}{- \rho_G} = \Delta h$

Data:

$h_1 = 20 cm; \rho_A = 0.789 \frac{g}{cm^3}; \rho_G = 1.26 \frac{g}{cm^3}$

$\frac{20 cm \times (0.789 - 1.26) \frac{g}{cm^3}}{- 1.26\frac{g}{cm^3}} = \Delta h$

$7.5 cm = \Delta h$

7 0

3 years ago

The weight of an objects can be calculated by multiplying mass by

Lana71 [14]

Acceleration due to gravity.

7 0

3 years ago

Read 2 more answers

If a train travels 80 miles north, 60 miles east, what’s the magnitude of its total displacement? Find the solution by drawing a

AnnZ [28]

Answer:

100 miles North East.

Explanation:

Please see attached photo for diagram.

In the attached photo, X represents the magnitude of the total displacement of the train.

Thus, we can obtain the value of X by using the pythagoras theory as illustrated below:

X² = 80² + 60²

X² = 6400 + 3600

X² = 10000

Take the square root of both side

X = √10000

X = 100 miles.

Therefore, the magnitude of the total displacement of the train is 100 miles North East.

8 0

3 years ago

The first law of motion applies to what?

lana66690 [7]

First law of motion- sometimes referred to as the law of inertia. An object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.

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3 years ago