How can light change matter
1 answer:
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Answer:
r₂ = 4 r
Explanation:
For this exercise let's use Newton's second law with the magnetic force
F = q v x B
bold letters indicate vectors, the magnitude of this expression is
F = q v B sin θ
in this case we assume that the angle is 90º between the speed and the magnetic field.
If we use the rule of the right hand with the positive charge, the thumb in the direction of the speed, the fingers extended in the direction of the magnetic field, the palm points in the direction of the force, which is towards the center of the circle, therefore the force is radial and the acceleration is centripetal
a = v² / r
let's use Newton's second law
F = ma
q v B = m v² / r
r =
Let's apply this expression to our case.
Proton 1
r = \frac{qB_1}{mv_1}
Proton 2
r₂ =
in the exercise indicate some relationships between the two protons
* v₁ = 2 v₂
v₂ = v₁ / 2
* B₂ = 2B₁
we substitute
r₂ =
r₂ = 4
r₂ = 4 r
Answer:
The net work produced is 30.37 KJ
The efficiency of cycle is 72.3%
Explanation:
For the net work produced, we have the formula:
Work = (Th - Tc)(Sh - Sc)(M)
Where,
Th = higher temperature = 800° C + 273 = 1073 k
Tc = lower temperature = 25° C + 273 = 298 k
Sh = specific entropy at higher temperature
Sc = specific entropy at lower temperature
M = molar mass of air
Using, ideal gas table to find entropy. The table is attached.
therefore,
Work = (1073 k - 298 k)(3.0485235 KJ/kg.k - 1.69528 KJ/kg.k)(0.02896 kg)
Work = (775 k)(1.3532435 KJ/kg.k)(0.02896 kg)
<u>Work = 30.37 KJ</u>
Now, for the efficiency (n), we have a formula:
n = 1 - Tc/Th
n = 1 - (298 k)/(1073 k)
<u>n = 0.723 = 72.3 %</u>
