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iragen [17]
3 years ago
9

One day in second grade, Chris drank chocolate milk before recess. She then played hard during recess and got sick from the heat

. That was years ago, but Chris never drank chocolate milk again because even thinking about chocolate milk makes her feel sick. Chris is most likely experiencing __________. A. food aversion B. superstition C. phobia D. learned helplessness
Physics
2 answers:
rosijanka [135]3 years ago
3 0

Answer:

its A i took the test

Explanation:

Advocard [28]3 years ago
3 0

Answer:

<u>A. Food Aversion</u>

It's right on ED2020, good luck!! Stay healthy and safe!!

<u />

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You are an astronaut floating alongside your space ship. If you throw a baseball with a speed of 10 m/s, you will move at:
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Answer:

D

Explanation:

There is no friction to stop you from moving BC you are in space, however you have a larger mass than the ball, so it takes more force to get you up to the same speed as the baseball. You will move in the opposite direction of the ball because you exerted force on the ball in one direction and therefore yourself in the opposing direction.

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3 years ago
Train cars are coupled together by being bumped into one another. Suppose two loaded train cars are moving toward one another, t
wolverine [178]

Answer:

final velocity =  0.08585m/s

Explanation:

We are taking train cars as our system. In this system no external force is acting. So we can apply the law of conservation of linear momentum.

The law of conservation of linear momentum states that the total linear momentum of a system remains constant if there is no external force acting on the system. That is total linear momentum before = total linear momentum after

total linear momentum before = linear momentum of first train car + linear momentum of second train car

We know that linear momentum = mv

where,

m = mass

v = velocity

thus,

total linear momentum before = m₁v₁ + m₂v₂

m₁ = mass of first train car = 135,000kg

v₁ = velocity of first train car = 0.305m/s

m₂ = mass of first second car =  100,000kg

v₂ = velocity of second train car =  −0.210m/s

Note: Momentum is a vector. So while adding momentum we should take account of its direction too. Here since second train car is moving in a direction opposite to that of the first one, we have taken its velocity as negative.

total linear momentum before = m₁v₁ + m₂v₂

                                                  = 135,000x0.305 + 100,000x(−0.210)

                                                  = 135,000x0.305 - 100,000x0.210

                                                  = 20,175 kgm/s

Now we have to find total linear momentum after bumping. After the bumping both the train cars will be moving together with a common velocity(say v).

Therefore, total linear momentum after = mv

m = m₁ + m₂ = 135,000 + 100,000 = 235,000

total linear momentum before = total linear momentum after

235,000v = 20,175

v =  \frac{20,175}{235,000}

  = 0.08585m/s

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