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harkovskaia [24]
3 years ago
8

Which planet was almost massive enough to have become a star?

Physics
2 answers:
Lostsunrise [7]3 years ago
4 0
Jupiter was almost big enough but failed to be a star
ololo11 [35]3 years ago
3 0
Jupiter ............................................
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The diameter of a spherical balloon that is being filled with air is increasing at the rate of 3 inches more than the time, t. W
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The description of the problem is a bit ambiguous as "<span>increasing at the rate of  </span>3 inches more than the time" can be interpreted in many ways. Assuming the increase rate is the (3+t) per second and as it expands for 3 seconds, then the diameter of the sphere would be:
d= (3 + t)*t
d= 3t + t^2= 18

r= 1/2 d 
r= 1/2*18= 9

volume= 4/3 * pi * r^3
volume= 4/3 * pi * 9^3
volume= 4/3 * pi * 729= 972 pi cubic inches
7 0
4 years ago
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In heat conduction analysis, the conversion of ____ energy into ____ energy in solids is called heat generation. check all that
Rudiy27

Heat conduction, also named as thermal conduction, is the heat flux in a body due to temperature difference and occurs by the movement of electrons within a body.

When all the available energies such as electrical energies, chemical energies or the nuclear energies are converted to the thermal energy, the the conversion process is called heat generation.

Thermal conduction is the process when the heat transfers from hotter region to  the colder region.

In heat conduction analysis, the conversion of electrical, chemical or nuclear energy into thermal energy in solids is called as heat generation.

To know more about thermal conduction,

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2 years ago
Which types of landfrom would you prefer for living?why?​
Makovka662 [10]

Answer:

Landforms affect where people build houses and communities. Many people live on plains because it is easy to travel and to farm on flat land. Other people live in valleys, which are the land between mountains or hills. The soil in valleys is good for farming.

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3 years ago
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Complete metamorphosis occurs in
lakkis [162]
It occurs in 4 stages
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3 years ago
Two identical parallel plate capacitors are given the same charge Q, after which they are disconnected from the battery. After C
postnew [5]

Answer:

U₁ > U₂

Explanation:

By definition, the capacitance of a capacitor, can be expressed as follows:

C = \frac{Q}{V} (1),

where Q is the charge on one of the terminals of the capacitor, and V,  the potential difference between them.

If the capacitors are of the parallel plate type, applying Gauss ' law to a gaussian surface defined as a pill box parallel to the surface of one of the plates (half outside the plate, half inside it) , the capacitance can be expressed as follows:

C = \frac{\epsilon*A}{d} (2)

where ε is the dielectric constant of the material that fills the space between plates, A is the area of one of the plates (assuming a constant surface charge density) and d is the distance between the plates.

If both capacitors have the same charge Q, as they are identical, the potential difference V must be the same for both capacitors also.

So, the electric potential energy, for both capacitors, can be written as follows:

Ue = U1 = U2 = \frac{1}{2}*\frac{Q^{2}}{C}

Now, if after being charged and disconnected (which means that the charge must keep the same), C₂ is filled with a dielectric, looking to the equation (2), we can see that the value of the capacitance, will increase, proportionally to the value of the dielectric constant of the dielectric.

If we analyze the expression (3) for the electric potential energy stored in the capacitor, as Q₂ = Q₁, and being C₂ = ε*C₁, this means that the electric potential energy U₂ must be lower than U₁, in the same factor ε, as follows:

U2 = \frac{1}{2}*\frac{Q^{2}}{C2} = \frac{1}{2}*\frac{Q^{2}}{\epsilon*C1} = \frac{1}{\epsilon} *( \frac{1}{2}*\frac{Q^{2}}{C1}) = \frac{1}{\epsilon} * U1

⇒ U₁ > U₂

3 0
3 years ago
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