Answer:
The maximum height reached by the body is 313.6 m
The time to return to its point of projection is 8 s.
Explanation:
Given;
initial velocity of the body, u = 78.4 m/s
at maximum height (h) the final velocity of the body (v) = 0
The following equation is applied to determine the maximum height reached by the body;
v² = u² - 2gh
0 = u² - 2gh
2gh = u²
h = u²/2g
h = (78.4²) / (2 x 9.8)
h = 313.6 m
The time to return to its point of projection is calculated as follows;
at maximum height, the final velocity becomes the initial velocity = 0
h = v + ¹/₂gt²
h = 0 + ¹/₂gt²
h = ¹/₂gt²
2h = gt²
t² = 2h/g

and C. corrosive, increases the concentration of hydrogen ions when added to water, forms hydrogen gas when it comes in contact with a metal, and formssalt and water when added to a base.
Answer:
The mass of a single paper is approximately 0.047 lb/paper which in SI Units is approximately 21.77 g/paper
Explanation:
The given information on the size and the weight of paper are;
The mass of a box of 500 sheets of paper = 24 lb
The number of sheets in the paper = 500 sheets
The dimensions of the paper = 17 in. × 22 in., which is equivalent to 43.18 cm × 55.88 cm
The mass of a single paper = The mass of the box of paper/(The number of sheets of paper present in the box)
The mass of a single paper = 24 lb/500 = 0.047 lb/paper
Given that 1 lb = 453.6 g, we have;
0.047 lb/paper = 0.047 lb/paper×453.6 g/(lb) = 21.77 g/paper
The mass of a single paper = 0.047 lb/paper = 21.77 g/paper.
Answer:
reflection and refraction?
Explanation:
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