1) According to the law of conservation of momentum ..
<span>Horiz recoil mom of gun (M x v) = horiz. mon acquired by shell (m x Vh) </span>
<span>1.22^6kg x 5.0 m/s = 7502kg x Vh </span>
<span>Vh = 1.22^6 x 5 / 7502 .. .. Vh = 813 m/s </span>
<span>Barrel velocity V .. .. cos20 = Vh / V .. ..V = 813 /cos20 .. .. ►V = 865 m/s </span>
<span>2) Using the standard range equation .. R = u² sin2θ /g </span>
<span>R = 865² x sin40 / 9.80 .. .. ►R = 49077 m .. (49 km)</span>
Answer:
The current at time t = 4.00 s is 0.766 A.
Explanation:
Given that,
The quantity of charge through a conductor is modeled as :
We need to find the current (in A) at time t = 4.00 s. We know that the rate of change of electric charge is called electric current. It is given by :
At t = 4 s
So, the current at time t = 4.00 s is 0.766 A. Hence, this is the required solution.
I believe the answer is all of the above.
Answer:
121km/h
Explanation:
Let speed of boat=xkm/h
Speed of water flow=33 km/h
Speed upstream=(x-33)km/h
Speed downstream=(x+33)km/h
Time=44 hrs
Time =77 hrs
We have to find the speed of boat.
Using the formula
Upstream distance=Downstream distance
Hence, the speed of boat=121km/h