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MatroZZZ [7]
3 years ago
5

The focus of counterinsurgency (coin) operations generally progresses through three stages. which stage concerns itself with exp

ansion of stability operations across contested regions, idealy using host nation (hn) forces?
a. late stage
b. post stage
c. middle stage
d. initial stage
Physics
1 answer:
posledela3 years ago
4 0
The term counter-insurgency refers to the actions (political and military) that aims in targeting the activities the revolutionaries. This operation consists of three stages. The stage that focuses on the expansion of stability operations onto the opposed regions by utilizing host nation forces belongs to the middle stage. Answer is C.
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After washing lettuce, you can dry the water from it using a salad spinner. You put the lettuce in the bowl, and then crank the
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A. The force that causes the water on the lettuce to come off the lettuce and go to the walls of the bowl is centrifugal force.

<h3>What is centrifugal force?</h3>

Centrifugal force is an inertial force that appears to act on all objects when viewed in a rotating frame of reference.

This force is directed away from the center around which the body is moving.

<h3>What is centripetal force?</h3>

This is force that acts on a body moving in a circular path and is directed towards the center around which the body is moving.

While centripetal force is directed towards to the center, the centrifugal force is directed away.

Thus, the force that causes the water on the lettuce to come off the lettuce and go to the walls of the bowl is centrifugal force.

Learn more about centrifugal force here: brainly.com/question/20905151

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6 0
2 years ago
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The intensity of light from a star varies inversely as the square of the distance. If you lived on a planet ten times farther aw
frosja888 [35]

Answer:

the intensity of the sun on the other planet is a hundredth of that of the intensity of the sun on earth.

That is,

Intensity of sun on the other planet, Iₒ = (intensity of the sun on earth, Iₑ)/100

Explanation:

Let the intensity of light be represented by I

Let the distance of the star be d

I ∝ (1/d²)

I = k/d²

For the earth,

Iₑ = k/dₑ²

k = Iₑdₑ²

For the other planet, let intensity be Iₒ and distance be dₒ

Iₒ = k/dₒ²

But dₒ = 10dₑ

Iₒ = k/(10dₑ)²

Iₒ = k/100dₑ²

But k = Iₑdₑ²

Iₒ = Iₑdₑ²/100dₑ² = Iₑ/100

Iₒ = Iₑ/100

Meaning the intensity of the sun on the other planet is a hundredth of that of the intensity on earth.

3 0
3 years ago
Look at the graph.<br><br><br><br><br><br> If the price of peaches increases, what can be expected?
Fittoniya [83]
There will be less peaches soled
5 0
3 years ago
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Two objects, A and B, each of mass o.22 kg, are moving at 0.34 m/s directly toward each other. What is the speed of Object A aft
ki77a [65]
Theoretically, if the objects have the same mass and are moving towards each other at a speed of 0.34m s^{-1}, after a perfectly elastic collision, the object A is supposed to move with the same velocity in the opposite direction.
6 0
3 years ago
An upward force of 32.6 N is applied via a string to lift a ball with a mass of 2.8 kg. (a) What is the gravitational force acti
Igoryamba

Answer:

a) Fg = -27.4 N

b) Fnet = 5.2 N

c) a = 1.9 m/s2

Explanation:

a)

  • There are two forces acting on the ball, one directed upward (assuming this direction as positive, along the y-axis) which is the tension on the string (lifting force), and another aimed downward, which is the attractive force due to gravity.
  • Applying the Newton's Universal Law of Gravitation to a mass close to the surface of the Earth (in this case the ball), we can take the acceleration due to gravity like a constant, that we call by convention g, equal to -9.8 m/s2.
  • So, we can write the following expression for Fg:

       F_{g} = m*g = 2.8 kg*(-9.8m/s2) = -27.4 N (1)

b)

  • The net force on the ball, will be just the difference between the lifting force (32.6 N) and the force due to gravity, Fg:

       F_{net} = T -F_{g} = 32.6 N - 27.4 N = 5.2 N  (2)

c)

  • According Newton's 2nd Law, the acceleration caused by a net force on a point mass (we can take the ball as one) is given by the following expression:

       a = \frac{F_{net} }{m} = \frac{5.2N}{2.8kg} = 1.9 m/s2  (3)

3 0
3 years ago
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