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4 years ago

Someone please help with this question

Physics

1 answer:

Alex787 [66]4 years ago

5 0

The first one might be faunal succsession and the 2nd one might be metamorphic rock

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An unmanned aerial vehicle (UAV) (or uncrewed aerial vehicle, commonly known as a drone) is an aircraft without a human pilot on

DaniilM [7]

Answer:

True

Explanation:

An unmanned areal vehicle is a device that is capable of flying with an on-board power source, receiver, wing propellers and the flight control board.

It functions on the Bernoulli's principle like an airplane does but is controlled remotely by a signal transmitting device with no man on-board.

It is used in various fields like construction, farming, remote sensing, defense, videography and aerial photography.

7 0

3 years ago

A street light is on top of a 9 foot pole. Joe, who is 3 feet tall, walks away from the pole at a rate of 4 feet per second. At

Gekata [30.6K]

Answer:2 ft/s

Explanation:

Given

Length of Pole is 9 ft

Length of Joe is 3 ft

Joe walks away from Pole at the rate 4 ft/s

Let Joe is x m away from Pole so its shadow length is x'

From Similar triangle concept

$\frac{x'}{x+x'}=\frac{3}{9}$

3x'=x+x'

x=2x'

and it is given $\frac{\mathrm{d} x}{\mathrm{d} t}=4 ft/s$

Differentiating

$\frac{\mathrm{d} x}{\mathrm{d} t}=2\frac{\mathrm{d} x'}{\mathrm{d} t}$

$4=2\times \frac{\mathrm{d} x'}{\mathrm{d} t}$

$\frac{\mathrm{d} x'}{\mathrm{d} t}=2 ft/s$

6 0

3 years ago

Unpolarized light passes through a vertical polarizing filter, emerging with an intensity I0. The light then passes through a ho

antiseptic1488 [7]

To solve this problem it is necessary to apply the concepts related to Malus' law. Malus' law indicates that the intensity of a linearly polarized ray of light that passes through a perfect analyzer with a vertical optical axis is equivalent to:

$I = I_0 cos^2(\theta)$

$I_0 =$ Indicates the intensity of the light before passing through the Polarizer,

I = The resulting intensity, and

$\theta$ = Indicates the angle between the axis of the analyzer and the polarization axis of the incident light.

There is 3 polarizer, then

For the exit of the first polarizer we have that the intensity is,

$I_2 = I_0cos^2(45)$

For the third polarizer then we have,

$I_3 = I_2 cos^{2}(45)$

Replacing with the first equation,

$I_3 = I_0cos^2(45)cos^{2}(45)$

$I_3 = I_0 (\frac{1}{2})(\frac{1}{2})$

$I_3 = I_0 \frac{1}{4}$

Therefore the transmitted intensity now is $\frac{1}{4}$ of the initial intensity.

5 0

4 years ago

If an element has 7 electrons how many of them will be in the 2nd energy level

inna [77]

Well first you can not go to the 2nd energy level without the first so the first takes up 2 electrons leaving you 5 electrons and the recommended amount is 8 electrons so you would have 5 electrons left

8 0

4 years ago

Read 2 more answers

If you are pushing on a box with a force of 20 N and there is a force of 7 N on the box due to sliding friction, what is the net

DIA [1.3K]

I think you would do 20+7 = 27N as the net force

7 0

3 years ago

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