The force on an object use Socratic glad to help ..
Answer is suspension.
Lets define all options.
<h3>Suspension:</h3>
In suspension the solute does not dissolve in liquid. When placed on table for some time, it will settle down at the bottom of the beaker. We can separate particles of solute easily from solvent through filtration.
<h3>Colloid:</h3>
In colloid particles of solute does not dissolve in liquid neither it is settle down. It floats through the solvent. It cannot be separated by filtration.
<h3>Solution:</h3>
In solution the particles of solute dissolve in to the solvent. We cannot identify them as separate. We cannot separate them by filtration. Salt and water solution is an example of it. Evaporation is the technique that is required to separate them.
<h3>Compound:</h3>
In compound, the two elements combine to form a new thing. Resultant/ compound have new or different properties other than its ingredients.
Now, the question was which of the following allow to settle out when sit on a table, so the answer is suspension. Suspension allows the particles to settle out when sit on a tables for some time.
Answer:
Minimum diameter of the camera lens is 22.4 cm
The focal length of the camera's lens is 300cm
Explanation:
y = Resolve distance = 0.3 m
h = Height of satellite = 100 km
λ = Wavelength = 550 nm
Angular resolution

From Rayleigh criteria

Minimum diameter of the camera lens is 22.4 cm
Relation between resolvable feature, focal length and angular resolution

The focal length of the camera's lens is 300cm
Action-reaction forces<span> act on different objects; </span>balanced forces<span> act on the same object. </span>Balanced forces<span> can result in acceleration, </span>action-reaction forces<span> cannot. ... Newton's Third Law of Motion does not apply to </span>balanced forces<span>.</span>
The current is defined as the ratio between the charge Q flowing through a certain point of a wire and the time interval,

:

First we need to find the net charge flowing at a certain point of the wire in one second,

. Using I=0.92 A and re-arranging the previous equation, we find

Now we know that each electron carries a charge of

, so if we divide the charge Q flowing in the wire by the charge of one electron, we find the number of electron flowing in one second: