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Anna71 [15]
3 years ago
6

Convert 13.4 degrees celcius into kelvin​

Chemistry
2 answers:
Alenkasestr [34]3 years ago
5 0

Answer:

286.55K

Explanation:

To convert to kelvin , add 237 .15

13.4\°C + 273.15 = 286.55K

Paladinen [302]3 years ago
4 0

Answer:

13.4 degrees celsius =

286.55 kelvins

Temperature

13.4

Celsius

286.55

Kelvin

Formula

13.4°C + 273.15 = 286.55K

Explanation:

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<em>❤</em><em> </em><em>❤</em><em> </em><em>❤</em><em> </em><em>❤</em><em> </em><em>❤</em><em> </em><em>❤</em><em> </em><em>❤</em><em> </em><em>❤</em><em> </em>

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The molar mass of H2O is 18.01 g/mol. The molar mass of O2 is 32.00 g/mol. What mass of H2O, in grams, must react to produce 50.
snow_lady [41]

112.5 g. The production of 50.00 g O2 requires 112.5 g H2O.

a) Write the partially balanced equation for the decomposition of water.

MM = 18.02 32.00

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b) Calculate the <em>moles of O2
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Moles of O2 = 50.00 g O2 × (1 mol O2/16.00 g O2) = 3.1250 mol O2


c) Calculate the <em>moles of water</em>

Moles of H2O = 3.1250 mol O2 × (2 mol H2O/1 mol O2)

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2 years ago
Gold forms a substitutional solid solution with silver. Compute the number of gold atoms per cubic centimeter for a silver-gold
Mama L [17]

<u>Answer:</u> The number of gold atoms per cubic centimeters in the given alloy is 1.83\times 10^{22}

<u>Explanation:</u>

To calculate the number of gold atoms per cubic centimeters for te given silver-gold alloy, we use the equation:

N_{Au}=\frac{N_AC_{Au}}{(\frac{C_{Au}M_{Au}}{\rho_{Au}})+(\frac{M_{Au}(100-C_{Au})}{\rho_{Ag}})}

where,

N_{Au} = number of gold atoms per cubic centimeters

N_A = Avogadro's number = 6.022\times 10^{23}atoms/mol

C_{Au} = Mass percent of gold in the alloy = 42 %

\rho_{Au} = Density of pure gold = 19.32g/cm^3

\rho_{Ag} = Density of pure silver = 10.49g/cm^3

M_{Au = molar mass of gold = 196.97 g/mol

Putting values in above equation, we get:

N_{Au}=\frac{(6.022\times 10^{23}atoms/mol)\times 48\%}{(\frac{48\%\times 196.97g/mol}{19.32g/cm^3})+(\frac{196.97g/mol\times 58\%}{10.49g/cm^3})}\\\\N_{Au}=1.83\times 10^{22}atoms/cm^3

Hence, the number of gold atoms per cubic centimeters in the given alloy is 1.83\times 10^{22}

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3 years ago
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