112.5 g. The production of 50.00 g O2 requires 112.5 g H2O.
a) Write the partially balanced equation for the decomposition of water.
MM = 18.02 32.00
2H2O → O2 + …
Mass/g = 50.00
b) Calculate the <em>moles of O2
</em>
Moles of O2 = 50.00 g O2 × (1 mol O2/16.00 g O2) = 3.1250 mol O2
c) Calculate the <em>moles of water</em>
Moles of H2O = 3.1250 mol O2 × (2 mol H2O/1 mol O2)
= 6.2500 mol H2O
d) Calculate the mass of water
Mass of H2O = 6.2500 mol H2O × (18.02 g H2O/1 mol H2O)
= 112.5 g H2O
<u>Answer:</u> The number of gold atoms per cubic centimeters in the given alloy is 
<u>Explanation:</u>
To calculate the number of gold atoms per cubic centimeters for te given silver-gold alloy, we use the equation:
where,
= number of gold atoms per cubic centimeters
= Avogadro's number = 
= Mass percent of gold in the alloy = 42 %
= Density of pure gold = 
= Density of pure silver = 
= molar mass of gold = 196.97 g/mol
Putting values in above equation, we get:
Hence, the number of gold atoms per cubic centimeters in the given alloy is
Answer:
A ) MOVIMIENTO
Explanation:
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