The mass of gas in the tank has been 222 g. Thus, option B is correct.
The volume occupied by 1 mole of gas at standard temperature and pressure has been 22.4 L.
<h3>Computation for the Mass of gas</h3>
The volume of gas in the tank has been given as 170 L.
The moles of gas in the tank has been:
The moles of gas in the tank has been 7.58 mol.
The molar mass of the gas has been 32.0 g/mol.
The mass of gas has been calculated as:
Thus, the mass of gas in the tank has been 222 g. Thus, option B is correct.
Learn more about mass of gas, here:
brainly.com/question/10035610
Answer:
D.)
Explanation:
The general equilibrium expression looks like this:
In this expression,
-----> K = equilibrium constant
-----> uppercase letters = formulas
-----> lowercase letters = balanced equation coefficients
In this case, all of the reactants and products are gases, so they should all be included in the expression. The products are in the numerator and the reactants are in the denominator. This makes the correct expression:
<----- Insert formulas
<----- Insert coefficients
This quote to me means how no one is perfect and you should appreciate yourself. Whoever you are right now, matters,
Answer:
V NH3 = 304.334 L
Explanation:
- 1 mol ≡ 6.02 E23 molecules
⇒ moles NH3 = (7.50 E24 molecules)×(mol/6.022 E23 molecules)
⇒ mole NH3 = 12.454 mol
assuming ideal gas:
STP:
∴ T = 25°C ≅ 298 K
∴ P = 1 atm
⇒ V NH3 = RTn/P
⇒ V NH3 = ((0.082 atm.L/K.mol)×(298 K)×(12.454 mol))/(1 atm)
⇒ V NH3 = 304.334 L