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Svetach [21]
3 years ago
8

(30 Points) You need to produce a buffer solution that has a pH of 5.02. You already have a solution that contains 10. mmol (mil

limoles) of acetic acid. How many millimoles of acetate (the conjugate base of acetic acid) will you need to add to this solution? The pKa of acetic acid is 4.74. Express your answer numerically in millimoles.
Chemistry
2 answers:
chubhunter [2.5K]3 years ago
8 0
<span>By definition:

pH = pKa + log [acetate]/ [acetic acid]

so

5.02 = 4.74 + log [acetate] / 10 mmole

10mmole = 10/1000 = 0.01 mole

5.02 = 4.74 + log [acetate] / 0.01

5.02 - 4.74 = 0.28 = log [acetate] /0.01


10^0.28 = </span><span>1.90546</span> = [acetate] / 0.01 <span>
[acetate] = 0.019 mole 

= 19 millimoles

</span>
ElenaW [278]3 years ago
3 0
<span>pH = pKa + log [acetate]/ [acetic acid] ( Handerso-Hasselbalch equation)

5.35 = 4.74 + log acetate / 0.010 moles

5.35 - 4.74 =0.61 = log acetate / 0.010

10^0.61 =4.1 = acetate / 0.010

moles acetate = 0.041

millimoles acetate required = 41</span>
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3 years ago
What tools would you use to measure the density of a rectangular block?
dimulka [17.4K]
A scale and a ruler. The scale to measure the mass, and a ruler to measure the volume.
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In what way does a temporary magnet provide an advantage over a permanent magnet?
Vilka [71]

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A temporary magnet allows the user to determine when it is magnetic.

7 0
2 years ago
Read 2 more answers
Which of the following lists includes only molecules?
riadik2000 [5.3K]
The only list containing molecules is list #4

NaCl, N2, and H2O are all made up of more than one element, making them molecules. The other lists contain an element. Mg, He, and Fe are elements, not molecules.

Hope this helps!
5 0
3 years ago
Tetrachloroethane is a valuable nonflammable solvent. It's percent composition is 14.31% carbon, 1.20% hydrogen, and 84.49% chlo
loris [4]
First take all percents and make them grams. Since you're not given a overall molar mass you can assume it is 100 and therefore the percents are their masses.
So you have 14.31g Carbon, 1.2g Hydrogen, and 84.49g of Chlorine. Next you divide each by their molar masses to get moles of each.

Carbon= <u>14.31</u>g       Hydrogen= <u>1.2</u>g         Chlorine= <u>85.49</u>g
               12.01g                         1.01g                         35.45g
          = 1.19moles                = 1.188moles          = 2.411moles

Next you divide each of those numbers by the smallest, in this case, Hydrogen.
Thus, 
    Carbon= <u>1.19moles</u>     Hydrogen= <u>1.188moles</u>   Chlorine= <u>2.411moles</u>
                   1.188moles                      1.188moles                   1.188moles 
             =1.002                               =1                                =2.02
These are all close enough to round, so your final empirical formula is: CHCl2
Hope that helps!!
 



6 0
3 years ago
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