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m_a_m_a [10]
3 years ago
7

what does the distance traveled by each component on the paper strip in paper chromatography depend on

Chemistry
2 answers:
ira [324]3 years ago
6 0

Answer:

PLZ FOLLOWING ME.........................

Luda [366]3 years ago
6 0
It depends on if the ink tested is soluble towards the solvent.So the more soluble it is towards such solvent the greater the distance travel.
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Based on the greenhouse effect, if the amount of carbon dioxide in the air decreased, what would happen?
choli [55]
A) the average global temp. Would decrease
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4 years ago
Explain the 2 main differences between ionic and covalent bonds and identify if the compound CaF2
Aloiza [94]

Answer:

yes. because look at the equation it will have an ionic bond

Explanation:

6 0
3 years ago
Current passes through a solution of sodium chloride. In 1.00 second, 2.68×1016Na+ ions arrive at the negative electrode and 3.9
EleoNora [17]

Answer : The current passing between the electrodes is, 1.056\times 10^{-2}A

Explanation :

First we have to calculate the charge of sodium ion.

q=ne

where,

q = charge of sodium ion

n = number of sodium ion = 2.68\times 10^{16}

e = charge on electron = 1.6\times 10^{-19}C

Now put all the given values in the above formula, we get:

q=(2.68\times 10^{16})\times (1.6\times 10^{-19}C)=4.288\times 10^{-3}C

Now we have to calculate the charge of chlorine ion.

q'=ne

where,

q' = charge of chlorine ion

n = number of chlorine ion = 3.92\times 10^{16}

e = charge on electron = 1.6\times 10^{-19}C

Now put all the given values in the above formula, we get:

q'=(3.92\times 10^{16})\times (1.6\times 10^{-19}C)=6.272\times 10^{-3}C

Now we have to calculate the current passing between the electrodes.

I=\frac{q}{t}+\frac{q'}{t}

I=\frac{4.288\times 10^{-3}}{1.00}+\frac{6.272\times 10^{-3}}{1.00}

I=1.056\times 10^{-2}A

Thus, the current passing between the electrodes is, 1.056\times 10^{-2}A

4 0
3 years ago
The specific heat capacity of graphite is 0.71 J/°C g.
Tom [10]

Answer:

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Explanation:

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8 0
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A gas with a vapor density greater than that of air, would be most effectively displaced out off a vessel by?
AURORKA [14]

A gas with a vapor density greater than that of air, would be most effectively displaced out off a vessel by ventilation.

The two following principles determine the type of ventilation: Considering the impact of the contaminant's vapour density and either positive or negative pressure is applied.

Consider a vertical tank that is filled with methane gas. Methane would leak out if we opened the top hatch since its vapour density is far lower than that of air. A second opening could be built at the bottom to greatly increase the process' efficiency.

A faster atmospheric turnover would follow from air being pulled in via the bottom while the methane was vented out the top. The rate of natural ventilation will increase with the difference in vapour density. Numerous gases that require ventilation are either present in fairly low concentrations or have vapor densities close to one.

3 0
2 years ago
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