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Diano4ka-milaya [45]
4 years ago
11

PLZ ANSWER THIS QUICKLY The diagram above shows a good web. What is a good web?

Chemistry
2 answers:
Sergeeva-Olga [200]4 years ago
7 0

Idk if it is multiple choice but if it is it is the first two, if it is a single answer then it is the first one

maw [93]4 years ago
3 0

It is the First two answer choices

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What is the reaction type of 3ZnS+ 2AlP = 1Zn3P2 + 1Al2S3 ?
adelina 88 [10]

Answer: double displacement

Explanation:

A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.  

The balanced chemical equation is:

3ZnS+2AlP\rightarrow Zn_3P_2+Al_2S_3

Thus as ions get exchanged , it is double displacement reaction.

4 0
3 years ago
The first ionization energy of mg is 735 kj/mol. calculate zeff.
Novay_Z [31]
2.25 I believe

Hope this helped!
STSN
7 0
3 years ago
Which type of bonding is found in all molecular substances?
Dmitrij [34]
The answer is covalent bonding. Molecular compounds are made of 2 or more nonmetals, and are therefore covalent. That is why another name for "molecular compound" is "covalent compound".
Answer: (1) covalent bonding

Hope this helped!! :D

4 0
3 years ago
Read 2 more answers
Determine the number of protons, electrons, and neutrons present in an atom of patassium. Explain how you determined your answer
Lady bird [3.3K]
Protons-19 because protons are equal to the atomic number which is 19 , electrons-19 electrons are equal to number of protons, neutrons-20 because the mass number of potassium is 39 so subtract 39 from 19 (atomic number) which gives us 20
3 0
3 years ago
In the laboratory a general chemistry student finds that when 2.84 g of KClO4(s) are dissolved in 107.70 g of water, the tempera
vredina [299]

Answer : The enthalpy change of dissolution of KClO_4 is 54.3 kJ/mole

Explanation :

Heat released by the reaction = Heat absorbed by the calorimeter + Heat absorbed by the water

q=[q_1+q_2]

q=[c_1\times \Delta T+m_2\times c_2\times \Delta T]

where,

q = heat released by the reaction

q_1 = heat absorbed by the calorimeter

q_2 = heat absorbed by the water

c_1 = specific heat of calorimeter = 1.55J/^oC

c_2 = specific heat of water = 4.184J/g^oC

m_2 = mass of water = 107.70 g

\Delta T = change in temperature = T_2-T_1=(22.80-20.34)=2.46^oC

Now put all the given values in the above formula, we get:

q=[(1.55J/^oC\times 2.46^oC)+(107.70g\times 4.184J/g^oC\times 2.46^oC)]

q=1112.3J=1.1123kJ

Now we have to calculate the enthalpy change of dissolution of KClO_4

\Delta H=\frac{q}{n}

where,

\Delta H = enthalpy change = ?

q = heat released = 1.1123 kJ

m = mass of KClO_4 = 2.84 g

Molar mass of KClO_4 = 138.55 g/mol

\text{Moles of }KClO_4=\frac{\text{Mass of }KClO_4}{\text{Molar mass of }KClO_4}=\frac{2.84g}{138.55g/mole}=0.0205mole

\Delta H=\frac{1.1123kJ}{0.0205mole}=54.3kJ/mole

Therefore, the enthalpy change of dissolution of KClO_4 is 54.3 kJ/mole

5 0
4 years ago
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