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jek_recluse [69]
3 years ago
14

The first ionization energy of mg is 735 kj/mol. calculate zeff.

Chemistry
1 answer:
Novay_Z [31]3 years ago
7 0
2.25 I believe

Hope this helped!
STSN
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To determine the concentration of chloride ion (Cl-) in a 100 mL sample of ground water, a chemist adds a large enough volume of
Orlov [11]

Answer:

[Cl^-]=232.3\frac{mgCl^-}{L}

Explanation:

Hello,

In this case, we can represent the chemical reaction as:

Cl^-(aq)+AgNO_3(aq)\rightarrow AgCl(s)+NO_3^-(aq)

In such a way, since the mass of the obtained silver chloride is 93.9 mg, we can compute the chloride ions in the ground water by using the following stoichiometric procedure whereas the molar mass of chloride ions and silver chloride are 35.45 g/mol and 143.32 g/mol respectively:

m_{Cl^-}=93.3mgAgCl*\frac{1mmolAgCl}{143.32mgAgCl}*\frac{1mmolCl^-}{1mmolAgCl} *\frac{35.45mgCl^-}{1mmolCl^-} =23.23mgCl^-

Finally, for the given volume of water in liters (0.100L), we compute the required concentration:

[Cl^-]=\frac{23.2mgCl^-}{0.100L}\\

[Cl^-]=232.3\frac{mgCl^-}{L}

Best regards.

5 0
4 years ago
Explain why photosynthesis and respiration are considered opposite processes when it comes to carbon.
lyudmila [28]
Respiration and Photosynthesis is different form each other because photosynthesis removes CO2 while respiration puts back CO2 

I hoped this helped!
3 0
3 years ago
What is the oxidation number for Ba? -2 +2 -1 +1
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7 0
3 years ago
Read 2 more answers
how do i caculate the trmperature change that 725 grams of aluminum will undergo when 2.35x10^4 Joules of thermal energy are add
sesenic [268]

Answer:

36°C

Explanation:

Given parameters:

Mass of aluminum = 725g

Quantity of heat  = 2.35 x 10⁴J

Unknown:

Temperature change  = ?

Solution:

To solve this problem, we simply use the expression below:

  The quantity of energy is given as:

          Q  = m C Δt

Q is the quantity of energy

m is the mass

C is the specific heat capacity of aluminum  = 0.9J/g°C

Δt is the change in temperature

  The unknown is Δt;

             Δt  = \frac{Q}{mc}    = \frac{2.35 x 10^{4} }{725 x 0.9}    = 36°C

4 0
3 years ago
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