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Alenkasestr [34]
3 years ago
5

From laboratory measurements, we know that a particular spectral line formed by hydrogen appears at a wavelength of 486.1 nanome

ters (nm). The spectrum of a particular star shows the same hydrogen line appearing at a wavelength of 485.9 nm. What can we conclude?
- The "star" actually is a planet.
- The star is moving away from us.
- The star is getting colder.
- The star is getting hotter.
- The star is moving toward us.
Physics
1 answer:
aksik [14]3 years ago
6 0

Answer:

The star is moving toward us

Explanation:

The wavelength of a distant object changes due to the change in the distance between the observer and the object. This is known as the Doppler effect.

If the wavelength decreases this means that the wavelength in going towards blue which is shorter wavelength. This is known as blue shift. If blue shift occurs then it means that the object is coming closer to the observer.

Hence, the star described here has blue shifted and is moving closer to us.

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PLEASE ANSWER ASAP BEFORE MY TEACHER AND MY MOM KILLES ME PLEASE ASAP
OlgaM077 [116]

Answer:

I don't know but I will try:

because the red color from the density column.

8 0
3 years ago
Read 2 more answers
How many visible stars does How many visible stars Taurus “the bull” have
dolphi86 [110]

Answer:

The Taurus "bull" is home to 500 stars, six of which are visible to the naked eye.

Explanation:

4 0
3 years ago
A series RLC circuit has a resonant frequency = 6.00 kHz. When it is driven at a frequency = 8.00 kHz, it has an
ANEK [815]

The resistance (R) of the circuit is 707.1 ohms and the inductance (L) is 0.032 H.

<h3>Resistance of the circuit</h3>

For the phase constant of 45⁰, impedance is equal to the resistance of the circuit.

Z= R\sqrt{2} \\\\R  = \frac{Z}{\sqrt{2} } \\\\R = \frac{1000}{\sqrt{2} } = 707.1 \ ohms

<h3>Resonant frequency</h3>

f = \frac{1}{2\pi \sqrt{LC} } \\\\6000 = \frac{1}{2\pi \sqrt{LC} } \\\\2\pi(6000) = \frac{1}{\sqrt{LC} } \\\\\sqrt{LC} = \frac{1}{2\pi (6000)} \\\\LC = (\frac{1}{2\pi (6000)})^2\\\\LC = 7.034 \times 10^{-10} \\\\ C = \frac{7.034 \times 10^{-10} }{L} ---(1)

<h3>At driven frequency</h3>

X_l- X_c = R\\\\\omega L - \frac{1}{\omega C}  = 707.1\\\\2\pi f L -  \frac{1}{2\pi fC} = 707.1\\\\2\pi (8000) L - \frac{1}{2\pi (8000) C } = 707.1\ \ --(2)\\\\

<em>solve 1 and 2 together</em>

2\pi(8000) L - \frac{L}{2\pi (8000)(7.034 \times 10^{-10})} = 707.1\\\\50272L - 28279.48L = 707.1\\\\L = 0.032 \ H

Learn more about impedance of RLC circuit here: brainly.com/question/372577

7 0
2 years ago
A child is riding a merry-go-round that has an instantaneous angular speed of 12 rpm. If a constant friction torque of 12.5 Nm i
sammy [17]

Answer:

-0.25 rad/s^2

Explanation:

The equivalent of Newton's second law for rotational motions is:

\tau = I \alpha

where

\tau is the net torque applied to the object

I is the moment of inertia

\alpha is the angular acceleration

In this problem we have:

\tau = -12.5 Nm (net torque, with a negative sign since it is a friction torque, so it acts in the opposite direction as the motion)

I=50.0 kg m^2 is the moment of inertia

Solving for \alpha, we find the angular acceleration:

\alpha = \frac{\tau}{I}=\frac{-12.5 Nm}{50.0 kg m^2}=-0.25 rad/s^2

3 0
3 years ago
5-A baseball is hit with a velocity of 15 m/s at an angle of 40° in the horizontal direction. What are the horizontal and vertic
borishaifa [10]

<u>Answer</u>

B•Horizontal=11.49 m/s  

Vertical=9.64 m/s

Using the concept of a trigonometric ratios,

sin θ  = y/hypotenuse

where y is the vertical component.

sin 40 = y/15

y = 15 × sin 40

  = 9.64 m/s

vertical component = 9.64 m/s

cos θ  = x/hypotenuse

where x is the horizontal component

cos 40 = x/15

x = 15 × cos 15

    =11.49

Horizontal component = 11.49 m/s

5 0
3 years ago
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