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melisa1 [442]
2 years ago
6

The c-cl bond dissociation energy in cf3cl is 339 kj/mol. What is the maximum wavelength of photons that can rupture this bond?

Physics
2 answers:
Rom4ik [11]2 years ago
8 0

Answer:

3.53*10^-7 color white "m

Where h= Planck constant

C=speed of light

Explanation:

Calculating energy required to dissociate the cl--cl Bond as this

Energy= +339*color white*kJmol

E=(339*10^3/6.022*10^23)=5.63*10^-19color white

But note from Planck equation

E=hf=h*c/lamda

Lamda= hc/E

=6.63*10^-34*3*10^8/5.63*10^-19

Lamda=3.532*10^-7 colorwhite*m

ruslelena [56]2 years ago
7 0

Answer:

3.53*10^{-7} m

Explanation:

Photon that can rupture the bonds are those with the energy of the bond dissociation energy. If we want to know the energy for each molecule we have to take into account that:

1mol=6.022*10^{23}molecule

Hence, we have

E_d=339\frac{10^{3}J}{mol}*\frac{1mol}{6-022*10^{23}molecules}=5.62*10^{-19}J/molecule

but the energy is also:

E_d=h\nu =\frac{hc}{\lambda}\\\\\lambda=\frac{hc}{E_d}

where h is the Planck's constant and c is the speed of ligth. By replacing we obtain:

\lambda=\frac{(6.62*10^{-34}Js)(3*10^{8}m/s)}{5.62*10^{-19}J}=3.53*10^{-7}m

hope this helps!

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2 years ago
How does increasing energy affect the amplitude of a wave?​
Crazy boy [7]

Answer:

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Explanation:

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5 0
3 years ago
A capacitor consists of two parallel plates, each with an area of 17.0 cm2 , separated by a distance of 0.150 cm . The material
My name is Ann [436]

Answer:

a)   C = 4,012 10⁻¹⁴ F, b)  Q = 1.6 10⁻¹¹ C , c)   U = 3.21 10⁻¹¹ J

Explanation:

a) The capacitance of a capacitor is

       C = k e₀ A / d

Let's calculate

       C = 4 8.85 10⁻¹² 17 10⁻⁴ / 0.150 10⁻²

       C = 4,012 10⁻¹⁴ F

b) let's look  the charge

        C = Q / ΔV

         Q = C ΔV

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c) The stored energy

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4 0
3 years ago
If an electron is accelerated from rest through a potential difference of 9.9 kV, what is its resulting speed
beks73 [17]

Answer:

v = 5.9 x 10⁷ m/s

Explanation:

The kinetic energy of the electron in terms of potential difference is given as:

K.E = eV--------------- equation (1)

where,

e = charge on electron = 1.6 x 10⁻¹⁹ C

V = Potential Difference = 9.9 KV = 9900 Volts

The kinetic energy in general is given as:

K.E = \frac{1}{2}mv^{2}\\--------- equation (2)

where,

m = mass of electron = 9.1 x 10⁻³¹ kg

v = speed of electron = ?

Therefore, comparing equation (1) and equation (2), we get:

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<u>v = 5.9 x 10⁷ m/s</u>

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Shkiper50 [21]

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