A peak = A Rms x Sq root 2
Therefore 3.6 x sq root of 2
A peak = 5.09
The answer would be B.
(V=IR, 12-10i, 12/10=1.2)
The answer is c: <span>1960 J
</span>Potential Energy :
<span>PE = m x g x h = 40*9.8*5=1960
</span>
Answer:
ω = 380π rad/s
Explanation:
The formula for the angular frequency is the oscillation frequency f (hertz) multiplied by 2π
ω = 2πf
then
ω = 2π(190)
ω = 380π rad/s
Answer:
If the voltage is increased then the electric field is higher, and electron velocity (average) is proportional to this field. Then you have an increase in speed. And current is total charge passing per time unit, so current is proportional to velocity value of charge (and to voltage in resistors and wire).
Explanation: