2 years ago

Using the word “more” to mean “I want another cookie” is an example of a( n):

Physics

1 answer:

svlad2 [7]2 years ago

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This duck and your brother

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1. An excited lithium atom emits a red light with wavelength a = 671nm. What is the corresponding photon energy? hc (6.63 x 10-3

Rudiy27

Answer:

E = 2,964 10⁻¹⁹ J

Explanation:

The energy of the photons is given by the Planck relation

E = h f

the speed of light is related to wavelength and frequency

c = λ f

we substitute

E = h c /λ

let's reduce the magnitude to the SI system

λ = 671 nm = 671 10⁻⁹ m

let's calculate

E = 6.63 10⁻³⁴ 3 10⁸ /671 10⁻⁹

E = 2,964 10⁻¹⁹ J

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The weight of the windsurfer is 700 newtons. Calculate the moment exerted by the windsurfer on the sailboat

borishaifa [10]

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2 years ago

In the photoelectric effect, a photon with an energy of 5.3 × 10–19 J strikes an electron in a metal. Of this energy, 3.6 × 10–1

valentina_108 [34]

Answer:

The velocity of the photo electron is $6.11\times 10^5\ m/s$ .

Explanation:

Given that,

Supplied energy, $E_s=5.3\times 10^{-19}\ J$

Minimum energy of the electron to escape from the metal, $E_e=3.6\times 10^{-19}\ J$

We need to find the velocity of the photo electron. The energy supplied by the photon is equal to the sum of minimum escape energy and the kinetic energy of the escaping electron. So,

$5.3\times 10^{-19}\ J=3.6\times 10^{-19}\ J+K\\\\K=5.3\times 10^{-19}-3.6\times 10^{-19}\\\\K=1.7\times 10^{-19}\ J$

The formula of kinetic energy is given by :

$K=\dfrac{1}{2}mv^2\\\\v=\sqrt{\dfrac{2K}{m}} \\\\v=\sqrt{\dfrac{2\times 1.7\times 10^{-19}}{9.1\times 10^{-31}}} \\\\v=6.11\times 10^5\ m/s$

So, the velocity of the photo electron is $6.11\times 10^5\ m/s$ .

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