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nika2105 [10]
3 years ago
8

Two kilograms of air in a piston-cylinder assembly undergoes an isothermal process from an initial state of 200K, 300kPa to 600k

Pa. a) How much entropy is generated in the process, in kJ/K. b) Calculate the amount of lost work.
Engineering
1 answer:
Norma-Jean [14]3 years ago
4 0

Answer:

a) 0.39795 kJ/K

b) 79.589.37 kJ

Explanation:

m = Mass of air = 2 kg

Temperature = 200 K

P₁ = Initial pressure = 300 kPa

P₂ = Final pressure = 600 kPa

R = mass-specific gas constant for air = 287.058 J/kgK

a) For isentropic process

\Delta S=mRln\frac{P_1}{P_2}\\\Rightarrow \Delta S=2\times 287.058ln\frac{300}{600}\\\Rightarrow \Delta S=-397.95\ J/K

∴ Entropy is generated in the process is 0.39795 kJ/K

b)

W=mRTln\frac{P_1}{P_2}\\\Rightarrow W=2\times 287.058\times 200ln\frac{300}{600}\\\Rightarrow W=-79589.37\ J

∴ Amount of lost work is 79.589.37 kJ

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Answer:

D

Explanation:

The air loss rate for a straight truck or bus with the engine off and the brakes applied should not be more than (D) 3 psi in one minute. An air loss rate  greater than 3 psi per minute can cause damage to air tank so the to avoid such condition the air leak rate cannot be more than 3 psi per minute.

7 0
3 years ago
.If aligned and continuous carbon fibers with a diameter of 6.90 micron are embedded within an epoxy, such that the bond strengt
Alina [70]

Answer:

the required minimum fiber length is 0.80365 mm

Explanation:

Given the data in the question;

Diameter D = 6.90 microns = 6.90 × 10⁻⁶ m

Bond strength ζ = 17 MPa

Shear yield strength ζ_y = 68 Mpa

tensile strength of carbon fibers 6t_{fiber = 3960 MPa.

To determine the minimum fiber length we make use of the following relation;

L = (6t_{fiber × D) / 2ζ

we substitute our given values into the equation;

L = ( 3960 × 6.90 × 10⁻⁶) / (2 × 17 )

L = 0.027324 / 34

L = 0.000803647 m

L = 0.000803647 × (1000) mm

L = 0.80365 mm

Therefore, the required minimum fiber length is 0.80365 mm

7 0
3 years ago
The dry unit weight of a soil sample is 14.8 kN/m3.
Jlenok [28]

Answer:

See attachment for completed question

Explanation:

Given that; Brainly.com

What is your question?

mkasblog

College Engineering 5+3 pts

The dry unit weight of a soil sample is 14.8 kN/m3.

Given that G_s = 2.72 and w = 17%, determine:

(a) Void ratio

(b) Moist unit weight

(c) Degree of saturation

(d) Unit weight when the sample is fully saturated

See complete solving at attachment

4 0
3 years ago
Me ayudas plis noce ​
alekssr [168]

Answer:

Explanation:

7 0
2 years ago
g Consider a thin opaque, horizontal plate with an electrical heater on its backside. The front end is exposed to ambient air th
xxTIMURxx [149]

Answer:

The electrical power is 96.5 W/m^2

Explanation:

The energy balance is:

Ein-Eout=0

qe+\alpha sGs+\alpha skyGsky-EEb(Ts)-qc=0

if:

Gsky=oTsky^4

Eb=oTs^4

qc=h(Ts-Tα)

\alpha s=\frac{\int\limits^\alpha _0 {\alpha l Gl} \, dl }{\int\limits^\alpha _0 {Gl} \, dl }

\alpha s=\frac{\int\limits^\alpha _0 {\alpha lEl(l,5800 } \, dl }{\int\limits^\alpha _0 {El(l,5800)} \, dl }

if Gl≈El(l,5800)

\alpha s=(1-0.2)F(0-2)+(1-0.7)(1-F(0-2))

lt= 2*5800=11600 um-K, at this value, F=0.941

\alpha s=(0.8*0.941)+0.3(1-0.941)=0.77

The hemispherical emissivity is equal to:

E=(1-0.2)F(0-2)+(1-0.7)(1-F(0-2))

lt=2*333=666 K, at this value, F=0

E=0+(1-0.7)(1)=0.3

The hemispherical absorptivity is equal to:

qe=EoTs^{4}+h(Ts-T\alpha  )-\alpha sGs-\alpha oTsky^{4}=(0.3*5.67x10^{-8}*333^{4})+10(60-20)-(0.77-600)-(0.3*5.67x10^{-8}*233^{4})=96.5 W/m^{2}

3 0
3 years ago
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