Answer:
The shear plane angle and shear strain are 28.21° and 2.155 respectively.
Explanation:
(a)
Orthogonal cutting is the cutting process in which cutting direction or cutting velocity is perpendicular to the cutting edge of the part surface.
Given:
Rake angle is 12°.
Chip thickness before cut is 0.32 mm.
Chip thickness is 0.65 mm.
Calculation:
Step1
Chip reduction ratio is calculated as follows:
![r=\frac{t}{t_{c}}](https://tex.z-dn.net/?f=r%3D%5Cfrac%7Bt%7D%7Bt_%7Bc%7D%7D)
![r=\frac{0.32}{0.65}](https://tex.z-dn.net/?f=r%3D%5Cfrac%7B0.32%7D%7B0.65%7D)
r = 0.4923
Step2
Shear angle is calculated as follows:
![tan\phi=\frac{rcos\alpha}{1-rsin\alpha}](https://tex.z-dn.net/?f=tan%5Cphi%3D%5Cfrac%7Brcos%5Calpha%7D%7B1-rsin%5Calpha%7D)
Here,
is shear plane angle, r is chip reduction ratio and
is rake angle.
Substitute all the values in the above equation as follows:
![tan\phi=\frac{rcos\alpha}{1-rsin\alpha}](https://tex.z-dn.net/?f=tan%5Cphi%3D%5Cfrac%7Brcos%5Calpha%7D%7B1-rsin%5Calpha%7D)
![tan\phi=\frac{0.4923cos12^{\circ}}{1-0.4923sin12^{\circ}}](https://tex.z-dn.net/?f=tan%5Cphi%3D%5Cfrac%7B0.4923cos12%5E%7B%5Ccirc%7D%7D%7B1-0.4923sin12%5E%7B%5Ccirc%7D%7D)
![tan\phi=\frac{0.48155}{0.8976}](https://tex.z-dn.net/?f=tan%5Cphi%3D%5Cfrac%7B0.48155%7D%7B0.8976%7D)
![\phi=28.21^{\circ}](https://tex.z-dn.net/?f=%5Cphi%3D28.21%5E%7B%5Ccirc%7D)
Thus, the shear plane angle is 28.21°.
(b)
Step3
Shears train is calculated as follows:
![\gamma=cot\phi+tan(\phi-\alpha)](https://tex.z-dn.net/?f=%5Cgamma%3Dcot%5Cphi%2Btan%28%5Cphi-%5Calpha%29)
![\gamma=cot28.21^{\circ}+tan(28.21^{\circ}-12^{\circ})](https://tex.z-dn.net/?f=%5Cgamma%3Dcot28.21%5E%7B%5Ccirc%7D%2Btan%2828.21%5E%7B%5Ccirc%7D-12%5E%7B%5Ccirc%7D%29)
.
Thus, the shear strain rate is 2.155.
Answer:
The young lady was his daughter.The shoemaker was frightened when he saw that she wants to sit near him and took his knife to frighten her and leave him alone to do his work
Explanation:
could uh name them since if i know any i would surely tryin help
Answer:
2.46 * 10⁵ W/m³
Explanation:
See attached pictures for detailed explanation.
Answer:
a) 23.89 < -25.84 Ω
b) 31.38 < 25.84 A
c) 0.9323 leading
Explanation:
A) Calculate the load Impedance
current on load side = 0.75 p.u
power factor angle = 25.84
= 0.75 < 25.84°
attached below is the remaining part of the solution
<u>B) Find the input current on the primary side in real units </u>
load current in primary = 31.38 < 25.84 A
<u>C) find the input power factor </u>
power factor = 0.9323 leading
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<em>attached below is the detailed solution </em>
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