Answer:
Check the explanation
Explanation:
Energy alance of 2 closed systems: Heat from CO2 equals the heat that is added to air in
1x0.723x
=3x0.780x
⇒
= 426.4 °K
The initail volumes of the gases can be determined by the ideal gas equation of state,
= 
= 0.201
The equilibrium pressure of the gases can also be obtained by the ideal gas equation
= 1x(8.314 28.97)x426.4+3x(8.314 44)x426.4
(0.201+1.275)
= 246.67 KPa = 2.47 bar
Answer:
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Explanation:
Answer:
a) 0.487
b) refrigeration load = 5.46w
c) cop = 2.24
d)ref load max = 12.43kw
Explanation:
Answer:
2ib
Explanation:
if you divide 10 divided by 2 it gives you 5 and then subtract it by 2.2 = 2.8
there goes your answer.
Answer:
(a) 0.243 m3/day
(b) 96 mg/l
(c) 0.426 m3/min
Explanation:
The sludge has an average solids concentration of 4 percent and considering TSS concentration in the influent of 240 mg/L then solids in sludge will be 0.04*240= 9.6 mg/L
Considering the average flow of 0.3 m3/s then mass of sludge per day will be given by 0.3*1000*9.6*60*60*24/1000000=248.832 kg/day
To get volume, considering specific gravity given as 1.025 and taking density of water as 1000 kg/m3 then density of sludge is 1025 kg/m3
Volume is mass/density hence 248.832/1025=0.2427629268292 m3/day
Approximately, the volume of sludge is 0.243 m3/day.
(b)
Efficiency of 60 percent is equivalent to 0.6
Efficiency=(influent concentration- flow rate)/influent concentration
0.6=(240-flow rate)/240
Flow rate= 96 mg/l
(c)
Cycle time= 0.243/0.57=0.4263157894736 m3/min
Rounded off, cycle time is 0.426 m3/day
