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3 years ago

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who wants points for now work just put any answer who wants points for now work just put any answer who wants points for now wor

k just put any answer

1 answer:

rodikova [14]3 years ago

7 0

Answer:

the engineer process is really fun. it's very useful for many things that you need to accomplish.

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A rod of aluminum has a square 4.5 mm × 4.5 mm cross section and length of 2.0 m. (A) What is the resistance of the rod along it

zimovet [89]

Answer:

The solution is attached below:

Explanation:

8 0

3 years ago

Elizabeth has been asked to design a pool umbrella that can withstand wind speeds of up to 30 miles per hour. Now that she under

zlopas [31]

Answer:

The correct option is;

D. She will need to research the problem even more

Explanation:

In other to properly design the pool umbrella that will be reliable and meet the needs of the particular customer, she will need to carry out a basic research about the environment where the pool umbrella is to be used, the presence of other factors that can impact on an idea for the pool umbrella.

She can then proceed to create a concept about the proposed pool umbrella, which is in the form of a paper concept

She will then proceed to carry out a more detailed study based on the paper concept that will consist of concept technology and application as well as functionality.

7 0

4 years ago

Read 2 more answers

A 900 kg car is accelerated from a speed of 10 m/s to 30 m/s. An estimated heat loss of 20 BTU's occurs during the acceleration.

Strike441 [17]

Answer:

Work = 651,1011 kJ

Explanation:

Let´s take the car as a system in order to apply the first law of thermodynamics as follows:

$E_{in}- E_{out}=E_{system,final}- E_{system,initial}$

Where

$E_{in}- E_{out}=(Q_{in}-Q_{out})_{heat}+(W_{in}-W_{out})_{work}+(Em_{in}-Em_{out})_{mass}$

And considering that there is no mass transfer and that the only energy flows that interact with the system are the heat losses and the work needed to move the car we have:

$E_{in}- E_{out}=-Q_{out}+W_{in}$

Regarding the energy system we have the following:

$E_{system,final}- E_{system,initial}=(U_{f}-U_{i})_{internal}+(1/2m(V^2_{f}-V^2_{i}))_{kinetic}+(mg(h_{f}-h_{i}))_{potential}$

By doing the calculations we have:

$E_{system,final}- E_{system,initial}=[0,1*900]_{internal}+[0,5*900(30^2-10^2)/1000)_{kinetic}+(900*10*(20-0)/1000)_{potential}\\E_{system,final}- E_{system,initial}=90+360+180=630kJ$

Consider that in the previous calculation, the kinetic and potential energy terms were divided by 1.000 to change the units from J to kJ.

Finally, the work needed to move the car under the required conditions is calculated as follows:

$W_{in}=Q_{out}+E_{system,final}- E_{system,initial}\\W_{in}=21,1011+630=651,1011kJ$

Consider that in the previous calculation, the heat loss was changed previously from BTU to kJ.

4 0

3 years ago

As a construction manager, Alex found a major issue with the client's design demands. He found out that the building design was

kipiarov [429]

Answer:

Which human resource skill helped Alex convince the client? its nagotiation

Explanation:

got it right on the test.

6 0

3 years ago

1. The sine rule is used when we are given either a) two angles and one side, or b) two sides and a non-included angle.

sammy [17]

Answer:

A. Yes

B. Yes

Explanation:

We want to evaluate the validity of the given assertions.

1. The first statement is true

The sine rule stipulates that the ratio of a side and the sine of the angle facing the side is a constant for all sides of the triangle.

Hence, to use it, it’s either we have two sides and an angle and we are tasked with calculating the value of the non given side

Or

We have two angles and a side and we want to calculate the value of the side provided we have the angle facing this side in question.

For notation purposes;

We can express the it for a triangle having three sides a, b, c and angles A,B, C with each lower case letter being the side that faces its corresponding big letter angles

a/Sin A = b/Sin B = c/Sin C

2. The cosine rule looks like the Pythagoras’s theorem in notation but has a subtraction extension that multiplies two times the product of the other two sides and the cosine of the angle facing the side we want to calculate

So let’s say we want to calculate the side a in a triangle of sides a, b , c and we have the angle facing the side A

That would be;

a^2 = b^2 + c^2 -2bcCosA

So yes, the cosine rule can be used for the scenario above

3 0

3 years ago