Answer:
Explanation:
Total weight being moved = 5000+1000+200
= 6200 lb .
Force applied = 700 lb
= 700 x 32 = 22400 poundal .
acceleration (a) = 22400 / 6200
= 3.613 ft /s²
To know velocity after 6 ft we apply the formula
v² = u² + 2as
v² = 0 + 2 x 3.613 x 6
43.356
v = 6.58 ft/s
Answer:
Math and Computer Skills. A qualified engineer should be good at math, at least through the level of calculus and trigonometry, and understand the importance of following the data when making design decisions.
Organization and Attention to Detail.
Curiosity.
Creativity.
Critical Thinking.
Intuition.
Explanation:
During some actual expansion and compression processes in piston-cylinder devices, the gases have been are the P1= P2.
<h3>What is the pressure?</h3>
Pressure is something that has the pressure that is physical and that causes the pressure is piston-cylinder devices.
During a few real enlargements and compression procedures in piston-cylinder devices, the gases were located to meet the connection PV n = C, wherein n and C are constants.
Read more about the pressure :
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Aesthetic elements are the components that are added to the design to be considered pleasing to the eye.
<h3>What are aesthetic elements?</h3>
They are those characteristics of an object that deal with the outward appearance or beauty of an object, that is, they are those elements that make it valuable, appreciable, relevant or transcendent.
To do this, the qualities must be in the design of the object but must also be perceived by the consumer, the aesthetic being what we like to perceive in objects.
Therefore, we can conclude that aesthetic elements are the components that are added to the design to be considered pleasing to the eye.
Learn more about aesthetic elements here: brainly.com/question/24568271
Answer:
The value of Modulus of elasticity E = 85.33 × 
Beam deflection is = 0.15 in
Explanation:
Given data
width = 5 in
Length = 60 in
Mass of the person = 125 lb
Load = 125 × 32 = 4000
We know that moment of inertia is given as
I = 1.40625 
Deflection = 0.15 in
We know that deflection of the beam in this case is given as
Δ = 
E = 85.33 ×
This is the value of Modulus of elasticity.
Beam deflection is = 0.15 in
