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irakobra [83]
4 years ago
7

Problem page liquid hexane reacts with gaseous oxygen gas to produce gaseous carbon dioxide and gaseous water . what is the theo

retical yield of water formed from the reaction of of hexane and of oxygen gas?
Chemistry
2 answers:
vitfil [10]4 years ago
5 0
C6H8 + 8O2 ===> 6CO2 + 4H2O ... balanced equation
moles hexane = 54.3 g x 1 mol/80 g = 0.679 moles
moles O2 = 78.5 g x 1 mol/32 g = 2.45 moles
Limiting reactant is Oxygen (O2) since need 8 x as much as C6H8
Theoretical yield of CO2 = 2.45 mole O2 x 6 mole CO2/8mole O2 = 1.84 moles CO2
1.84 moles CO2 x 44 g/mol = 80.9 g (answer to 3 sig figs)
depending on if your question possesses this values
Olin [163]4 years ago
3 0

Answewater

water

Explanation:

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Determine el PH y el % de disociación de una solución de ácido débil, sabiendo que se disuelven 20 gramos del ácido (masa molar=
IceJOKER [234]

Answer:

pH = 4.27. Porcentaje de disociación: 0.03%

Explanation:

El pH de un ácido débil, HX, se obtiene haciendo uso de su equilibrio:

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Donde la constante de equilibrio, Ka, es

Ka = 1.65x10⁻⁸ = [H⁺] [X⁻] / [HX]

Como los iones H⁺ y X⁻ vienen del mismo equilibrio podemos decir:

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[HX] es:

20g * (1mol/55g) = 0.3636moles / 2.100L = 0.1732M

Reemplazando es Ka:

1.65x10⁻⁸ = [H⁺] [H⁺] / [0.1732M]

2.858x10⁻⁹ = [H⁺]²

5.35x10⁻⁵M = [H⁺]

pH = -log[H⁺]

<h3>pH = 4.27</h3>

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Reemplazando

5.35x10⁻⁵M / 0.1732M * 100

<h3>0.03%</h3>
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3 years ago
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Tanzania [10]

Answer:

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  (70.0g)/(44.01 g/mol)·(22.4 L/mol) ≈ 35.6 L

5 0
3 years ago
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